A = (1/2)(8yd)(15yd) = 60 yd²
IJ=x-4
JK=5x+12
IK=9x-19
IJ+JK=IK
(x-4)+(5x+12)=(9x-19)
x-4+5x+12=9x-19
6x+8=9x-19
6x+8-6x+19=9x-19-6x+19
27=3x
3x=27
3x/3=27/3
x=9
IJ=x-4=9-4→IJ=5
JK=5x+12=5(9)+12=45+12→JK=57
IK=9x-19=9(9)-19=81-19→IK=62
Answer: Option B. IJ=5, JK=57, IK=62
Answer:
If we are working in a coordinate plane where the endpoints has the coordinates (x1,y1) and (x2,y2) then the midpoint coordinates is found by using the following formula:
midpoint=(x1+x22,y1+y22)
Step-by-step explanation:
An odd number of negative factors will give you a negative.
Answer:
a. 10√2
Step-by-step explanation:
hey, just use Pythagoras theorem
h²=p²+b²=10²+10²=100+100=200
h²=200, h= √200 =√(100×2)=√100×√2=10√2