-3+11p
first you add 1+2p that gets you -3 then you do 9p-4 and you get 11p from there you can either solve it, or leave it as is, depending on what your teacher wants.
Answer:
7
Step-by-step explanation:
When you match the form
... ax² + bx + c = 0
to the equation
... 3x² + 5x + 7 = 0
it is reasonable to conclude that ...
... a = 3, b = 5, c = 7.
_____
The question presumes you are familiar with the form
... ax² +bx +c = 0
which is often used as the representation of a general quadratic equation. This lets us use a, b, and c instead of specific numbers, to talk about ways of factoring, graphing, or solving equations like this.
![\sqrt[3]{x + 1} = 2](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20%20%3D%202)
Let us cube both sides.
![= > (\sqrt[3]{x + 1} ) ^{3} = {2}^{3}](https://tex.z-dn.net/?f=%20%3D%20%20%3E%20%20%28%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20%29%20%5E%7B3%7D%20%20%3D%20%20%7B2%7D%5E%7B3%7D%20)
Now, it will be only x + 1.

Transpose 1 to the Right Hand Side.

Now, subtract.

<u>Answer</u><u>:</u>
x = 7
Hope you could understand.
If you have any query, feel free to ask.
Answer:
144 ft
Step-by-step explanation:
The speed decreases linearly by 32 ft/sec/sec, so will be zero after ...
(96 ft/s)/(32 ft/s²) = 3 s
The average speed over that period is half the initial speed, so the distance covered between the ground and the maximum height is ...
(3 s)(96 ft/s)/2 = 144 ft
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<em>Alternate solution</em>
The relationship between velocity and distance for a constant acceleration is ...

For an initial velocity of 96 ft/s, a final velocity (at the top of travel) of 0, and the given acceleration, we have ...
