Derrick made a goal for 2 points during the basketball game. The path of the balls height in feet can be modeled by y=-x^2 -2x +
24.use a graph of the function to determine the maximum height of the ball
1 answer:
Given:
<span>y= -x^2 - 2x + 24.
graph of an equation of the form y = ax</span>² + bx + c ; a < 0, the parabola opens downward
a = -1 ; b = - 2 ; c + 24
x = 0 ; y = 0² - 2(0) + 24 ; y = 24 (0,24) y-coordinate
x = [-b <u>+</u> √(b² - 4ac)] / 2a
x = [-(-2) <u>+</u> √(-2²) - 4(-1)(24)] / 2(-1)
x = [2 <u>+</u> √(4 + 28)] / -2
x = [2 <u>+</u> √32] / -2
x = [2 <u>+</u> √(4*8)] / -2
x = [2 <u>+</u> 2 √8] / -2
x = 2 (1 <u>+</u> √8) / -2
x = 1 <u>+</u> √8 / -1
x = - 1 + √8 ; x = - 1 - √8
x = -1 + 2.83 ; x = -1 - 2.83
x = 1.83 ; x = -3.83
average:
1.83 + 3.83 = 5.66
5.66 / 2 = 2.83 midpoint
y = -(2.83)² - 2(2.83) + 24
y = - 8 - 5.66 + 24
y = 10.34
The maximum height of the ball is 10.34 feet. (2.83,10.34)
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