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8_murik_8 [283]
3 years ago
13

Freshman math please help as soon as possible!

Mathematics
1 answer:
kodGreya [7K]3 years ago
7 0
No, they are not correct
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Jose goes to the bodega. He
AysviL [449]

Answer:

1 bag of chips cost $1.25

Step-by-step explanation:

total money spent minus cost of soda = price of 2 bags of chips

$4.00- $1.50 = $2.50

2 bags of chips divided by 2 = price for one bag

$2.50 / 2 = $1.25

3 0
3 years ago
How many fifths are in 2 3/5
Setler [38]
2 \frac{3}{5}= \frac{2*5+3}{5}= \frac{10+3}{5}=\frac{13}{5}
Answer you are looking for is 13
3 0
3 years ago
What is the slope of the line​
wolverine [178]

Answer:

negative one over seven

8 0
3 years ago
Ammonia, nh3 (delta.hf = –46.2 kj), reacts with oxygen to produce water (delta.hf = –241.8 kj) and nitric oxide, no (delta.hf =
poizon [28]

The enthalpy change (ΔH) for the reaction given the data from the question is –900.8 KJ

<h3>Data obtained from the question</h3>
  • 4NH₃ + 5O₂ —> 6H₂O + 4NO
  • Enthalpy of ammonia, NH₃ = –46.2 KJ
  • Enthalpy of Oxygen = 0 KJ
  • Enthalpy of water, H₂O = –241.8 KJ
  • Enthalpy of nitric oxide, NO = 91.3 KJ
  • Enthalpy change (ΔH) =?

<h3>How to determine the enthalpy change</h3>

ΔHrxn = ∑ΔH(products) - ∑ΔH(reactants)

ΔHrxn = ∑[H(H₂O) + H(NO)] - ∑[H(NH₃) + H(O₂)]

ΔHrxn = [(6 × –241.8) + (4 × 91.3)] – [(4 × –46.2) + (5×0)]

ΔHrxn = –1085.6 + 184.8

ΔHrxn = –900.8 KJ

Learn more about enthalpy change:

brainly.com/question/2364362

#SPJ4

4 0
2 years ago
Lesson Quiz 9-3 1. What are the solutions of each equation? Use a graph of the related function. a. x2 + 4 = 4 b. x2 + 16 = 0 c.
dedylja [7]

Answer:

soryyyyyyyyy

Step-by-step explanation:

soryyyyyyyyyy

8 0
3 years ago
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