All categories

3 years ago

Plss tell me guy's plssssssssssssssssssssssssssssssssssssssssssssss

Mathematics

2 answers:

Ksenya-84 [330]3 years ago

8 0

Answer:

According to my equation it's 20°

Kipish [7]3 years ago

4 0

2x=5x-60
-3x=-60
X=20

So the angle is 40

You might be interested in

an NFL team kicker misses 2 out of every 11 field goals if he missed 8 filed goals throughout the season how many did he attempt

Aleks [24]

For this equation, you want to do it in fractions/ratios to properly solve it. You would have his average misses out of every field goal and his real missed attempts over total. It would look like this

$\frac{2}{11}$ = $\frac{8}{x}$

You want to solve for x since x is the total amount of field goals that he attempted. You can do this by doing cross multiplication:

(2)(x) = (8)(11)

From here you can get:

2x = 88

Divide each side by 2 to isolate x and you get:

x= 44

So he made a total of 44 field goals.

3 0

3 years ago

Read 2 more answers

Is 4 greater than 4.002?

elixir [45]

No because 4=4.00000 and there is that much more than 4.00000 so 4.002 is more

5 0

3 years ago

Read 2 more answers

Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =

swat32

Answer:

Test statistic, $t_{s} = -0.603$ (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

$\bar{d} = \frac{\sum x-y}{n}$

$\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625$

Standard deviation: $SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1} }$

$\sum d^{2} = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2} = 63$

$SD = \sqrt{\frac{63 - 8 * (-0.625)^2}{8-1} }$

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

$t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n} } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8} }$

$t_{s} = -0.6033$

6 0

3 years ago

HELP ME pleaseeeee ill mark you as brainiest if I get two answers

sergiy2304 [10]

Question 9

Given the segment XY with the endpoints X and Y

Given that the ray NM is the segment bisector XY

NM divides the segment XY into two equal parts

XM = MY

given

XM = 3x+1

MY = 8x-24

so substituting XM = 3x+1 and MY = 8x-24 in the equation

XM = MY

3x+1 = 8x-24

8x-3x = 1+24

5x = 25

divide both sides by 5

5x/5 = 25/5

x = 5

so the value of x = 5

As the length of the segment XY is:

Length of segment XY = XM + MY

= 3x+1 + 8x-24

= 11x - 23

substituting x = 5

= 11(5) - 23

= 55 - 23

= 32

Therefore,

The length of the segment = 32 units

Question 10)

Given the segment XY with the endpoints X and Y

Given that the line n is the segment bisector XY

The line divides the segment XY into two equal parts at M

XM = MY

given

XM = 5x+8

MY = 9x+12

so substituting XM = 5x+8 and MY = 9x+12 in the equation

XM = MY

5x+8 = 9x+12

9x-5x = 8-12

4x = -4

divide both sides by 4

4x/4 = -4/4

x = -1

so the value of x = -1

As the length of the segment XY is:

Length of segment XY = XM + MY

= 5x+8 + 9x+12

= 14x + 20

substituting x = 1

= 14(-1) + 20

= -14+20

= 6

Therefore,

The length of the segment XY = 6 units

8 0

3 years ago

There are 24 pictures on a roll of film. Adelle had 84 pictures from her trip home. She said that 12 other pictures were spoiled

Anna71 [15]

Answer:

Total pictures = 84+12 = 96

roll of films = 96 / 24 = 4

she used 4 rolls

7 0

2 years ago