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Angle A of triangle ABC will be ...
∠A = θ₂ -θ₃ = 77° -26° = 51°
Angle B of triangle ABC will be ...
∠B = 180° -θ₂ -θ₁ = 180° -77° -44° = 59°
Then angle C will be ...
∠C = 180° -∠A -∠B = 180° -51° -59° = 70°
By the Law of Sines,
a/sin(∠A) = c/sin(∠C)
a = c×sin(∠A)/sin(∠C)
a = (57 yd)×sin(51°)/sin(70°) ≈ 47.14 yd
The distance from B to C is 47.14 yd.
Answer:
37
Step-by-step explanation:
I'm having trouble explaining this one, sorry
850=4
The explanation is I need points to help
Me
Get this essay done so I have no idea honestly good luck
Answer:
1. a = 21°
2. b = 70°
3. c = 89°
Step-by-step explanation:
1. Determination of the value of a.
a = 21° (vertically opposite angles are equal)
2. Determination of the value of b.
From the question given above,
110 + b = 180 (sum of angles on a straight line)
Collect like terms
b = 180 – 110
b = 70°
3. Determination of the value of c.
a + b + c = 180 (sum of angles in a triangle)
a = 21°
b = 70°
c =?
21 + 70 + c = 180
91 + c = 180
Collect like terms
c = 180 – 91
c = 89°
