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sladkih [1.3K]
3 years ago
15

Two vectors are given by a with arrow = 3 î + 6 ĵ and b with arrow = -1 î + ĵ. (a) find a with arrow ✕ b with arrow.

Mathematics
1 answer:
Kisachek [45]3 years ago
5 0
A  i think im not sure

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Write the equation of the line, in slope-intercept form, that contains the points (-1,-2) and (1,2)
Bad White [126]
Slope intercept is y=mx+b
m=slope
slope if found by
m=(y1-y2)/(x1-x2)
(x,y)
(-1,-2) and
(1,2)
x1=-1
y1=-2
x2=1
y2=2


m=(-1-1)/(-2-2)
m=-2/-4
m=1/2


y=1/2x+b
solve fo by subsituting one x value
(1,2)
x=1
y=2
2=1/2(1)+b
2=1/2+b
subtract 1/2
3/2=b


equation is
y=1/2x+3/2

4 0
3 years ago
X/15=5<br> whats the value of x?
SpyIntel [72]

Answer:

x=75

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
I skipt thought the lesson pls help
Karo-lina-s [1.5K]

Answer:

I'm not sure but the last one I think is wroght

4 0
3 years ago
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Write an equation of the line that passes through the given points.<br> (-1,5) and (2, - 7)
Vanyuwa [196]

Answer:

The equation of the straight line is 4x +y = 1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given points are (-1,5) and ( 2,-7)

Slope of the line

m =\frac{y_{2}-y_{1}  }{x_{2} -x_{1} }  =\frac{-7-5}{2-(-1)}  = \frac{-12}{3} = -4

slope of the line m = -4

<u><em>Step(ii):-</em></u>

The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4

y - y_{1} = m( x-x_{1} )

y - 5 = -4 ( x-(-1))

y -5 = -4 x -4

4 x + y -5 +4=0

4x +y -1 =0

<u><em>Final answer:-</em></u>

The equation of the straight line is 4x +y = 1

<u><em>  </em></u>

6 0
2 years ago
Select the point that is a solution to the system of inequalities. Yx^2-4?
ziro4ka [17]

Answer:

C (1,2)

Step-by-step explanation:

The point that is a solution must satisfy both inequalities;

The inequalities are;

y\:

y\:>\:x^2-4

Point A

(4,0)

0\:: True

0\:>\:16-4:False

Point B (0,4)

4\:: False

4\:>\:0-4:True

Point C (1,2)

2\:: True

2\:>\:1-4:True

Point D(-2,-4)

-4\:: True

-4\:>\:4-4:False

The correct answer is C.

4 0
3 years ago
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