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Grace [21]
3 years ago
7

Let F be the function given by f(x)= 2xe^x. Determine the interval(s) on which the graph is concave down.

Mathematics
1 answer:
Vika [28.1K]3 years ago
7 0
Hello,

y=2xe^x
y'=2(e^x+xe^x)=2(x+1)e^x
y''=2(e^x+(x+1)e^x)=2(x+2)e^x

x     |-infinite   -2  0    +infinite
e^x | ++++++++++++++++++
x+2 |------------0 +++++++++++
y''    | -----------0 +++++++++++

y''<0 if x<-2
<span>The interval on which the graph is concave down is (-infinite -2[</span>

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Answer:

The answer is A

Step-by-step explanation:

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Massimo spent $90. riding the bus. Each bus ride cost $2.50. Write and solve an equation to determine how many times Massimo rod
Varvara68 [4.7K]

Answer:

$90 ÷ $2.50 = 36

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Vadim26 [7]

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Step-by-step explanation:

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Question 17
RoseWind [281]

Answer:

Perpendicular

Step-by-step explanation:

Remember that:

  • Two lines are parallel if their slopes are the same.
  • Two lines are perpendicular is their slopes are negative reciprocals.
  • And two lines are neither (a.k.a intersecting) if they are neither parallel nor perpendicular.

So, let's find the slope of QR and ST.

QR)

We can use the slope formula:

m=\frac{y_2-y_1}{x_2-x_1}

Let Q(-6, 11) be (x₁, y₁) and R(2, -1) be (x₂, y₂). Substitute:

m=\frac{-1-11}{2-(-6)}

Subtract:

m=-12/8=-3/2

So, the slope of QR is -3/2.

ST)

Let S(-4, 8) be (x₁, y₁) and T(-1, 10) be (x₂, y₂). Substitute:

m=\frac{10-8}{-1-(-4)}

Subtract:

m=2/3

So, the slope of ST is 2/3.

The negative reciprocal of -3/2 is 2/3.

And the negative reciprocal of 2/3 is -3/2.

So, the slopes are indeed negative reciprocals of each other.

So, QR and ST are perpendicular.

7 0
3 years ago
Read 2 more answers
|MATH|
blondinia [14]
The answer is (1,1) Hope this helps :)
7 0
3 years ago
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