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trasher [3.6K]
3 years ago
15

How do you determine if terms are like terms? Be specific

Mathematics
1 answer:
Talja [164]3 years ago
3 0
Like terms have to have the same variables and the variables have to have the same powers.

3x and 6x are like terms.
3x and 6y are not.

4y^2 and 7y^2 are like terms.
4y^3 and 7y^6 are not.

2xy and 5xy are like terms.
2xy^2 and 5x^2y are not
2xy^2 and 5xy are not.
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Which expression is equivalent to - 2/5(x+0.8) + 1/50?
Rudik [331]

Answer:

-0.4x - 0.30 or -\frac{2}{5} - \frac{3}{10}

Step-by-step explanation:

Change all the fractions to decimals.

-2/5 = -0.4 Distribute that over x and 0.8 1/50 = 0.02

you get -0.4x -0.32 + 0.02

Change all the decimals to fractions.

0.8 is 8/10 so -2/5 times 8/10 is -16/50

-2x/5 - 16/50 + 1/50 add or subtract the fractions to get -15/50 Then reduce (÷5)

-2x/5 - 3/10

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4 years ago
What is the mean of this data set? 69, 59, 70, 74, 68, 71, 58
Hunter-Best [27]
The mean (or average) for the data set is 67.428
3 0
4 years ago
What are the answers to these??
QveST [7]

8)23a+13

9)-21b+84

10)17c+2

5 0
3 years ago
Find the equation of a parabola with a focus at (0,-1) and a directrix at y = 4.
Anastasy [175]

Answer:

  y = -1/10x^2 +2.5

Step-by-step explanation:

The distance from focus to directrix is twice the distance from focus to vertex. The focus-directrix distance is the difference in y-values:

  -1 -4 = -5

So, the distance from focus to vertex is p = -5/2 = -2.5. This places the focus 2.5 units below the vertex. Then the vertex is at (h, k) = (0, -1) +(0, 2.5) = (0, 1.5).

The scale factor of the parabola is 1/(4p) = 1/(4(-2.5)) = -1/10. Then the equation of the parabola is ...

  y = (1/(4p))(x -h) +k

  y = -1/10x^2 +2.5

_____

You can check the graph by making sure the focus and directrix are the same distance from the parabola everywhere. Of course, if the vertex is halfway between focus and directrix, the distances are the same there. Another point that is usually easy to check is the point on the parabola that is even with the focus. It should be as far from the focus as it is from the directrix. In this parabola, the focus is 5 units from the directrix, and we see the points on the parabola at y=-1 are 5 units from the focus.

5 0
4 years ago
Lesson 19 problem set module three grade 7?
yanalaym [24]

Answer:

what is the problem

Step-by-step explanation:

8 0
3 years ago
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