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garri49 [273]
3 years ago
8

Solve for x your answer must be simplified. -4+x<9

Mathematics
2 answers:
bezimeni [28]3 years ago
8 0

Answer:

x<13

Step-by-step explanation:

To solve this, we want to have the isolate the variable x on the left side, by itself without a coefficient. All we have to do to do this is add 4 to both sides, cancelling out the -4 and getting x<13

Mars2501 [29]3 years ago
5 0

Answer:

x = 13 + y

Step-by-step explanation:

Simplify:

-4 + x = y + 9

Reorder the terms:

-4 + x = 9 + y

Move all terms containing x to the left all other terms to the right

Add 4 to each side of the equation

-4 + 4 + x = 9 + 4 + y

Combine like terms: -4 + 4 = 0

0 + x = 9 + 4 + y

x = 9 + 4 + y

9 + 4 = 13x = 13 + y

Answer:

x = 13 + y

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Answer:

t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28    

The degrees of freedom are given by

df=n-1=17-1=16  

The p value would be given by this probability:

p_v =P(t_{(16)}  

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

Step-by-step explanation:

Information given

\bar X=8.19 cm^3 represent the sample mean

s=0.8 cm^3 represent the sample deviation

n=17 sample size  

\mu_o =9.02 represent the value to verify

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value

System of hypothesis to check

We want to check if the true mean is less than the normal value of 9.02 cm^3, the system of hypothesis would be:  

Null hypothesis:\mu \geq 9.02  

Alternative hypothesis:\mu < 9.02  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28    

The degrees of freedom are given by

df=n-1=17-1=16  

The p value would be given by this probability:

p_v =P(t_{(16)}  

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

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3 years ago
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Answer:

  see below

Step-by-step explanation:

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