P(x) = (x + 3)Q(x) + R
<span> P(-3) = (0)Q(x) + R </span>
<span>i P(-3) = R </span>
<span>Now, P(-3) = (-3)⁴ - 9(-3)³ - 5(-3)² - 3(-3) + 4
</span>So
<span>P(-3) = 81 + 243 - 45 + 9 + 4 </span>
<span>=. 292
hope it helps</span>
Answer: Does not exist.
Step-by-step explanation:
Since, given function, f(x) = 6x tan x, where −π/2 < x < π/2.
⇒ f(x) = 
And, for vertical asymptote, cosx= 0
⇒ x = π/2 + nπ where n is any integer.
But, for any n x is does not exist in the interval ( -π/2, π/2)
Therefore, vertical asymptote of f(x) where −π/2 < x < π/2 does not exist.
Use photo math. or mathpapa to help you solve the equation
Know the order of operations. However, one of the trickiest things about solving an algebra<span> equation as a beginner is knowing where to start. Luckily, there's a specific order for solving these problems: first </span>do<span> any math operations in parentheses, then </span>do<span> exponents, then multiply, then divide, then add, and finally subtract</span>
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