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prohojiy [21]
3 years ago
5

In a ΔPQR, ∠Q = 90 , PQ = 5 cm, QR = 12cm. If QS is the altitude then QS is equal to?

Mathematics
1 answer:
ryzh [129]3 years ago
4 0

Answer:

QS EQUAL TO IS ?

Step-by-step explanation:

In a ΔPQR, ∠Q = 90 , PQ = 5 cm, QR = 12cm. If QS is the altitude then QS is equal to?

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2 tens & 15 ones is equal to 35

Because 2 tens = 20

15 already has a ten so add +10 to 20

30+5 is 35.

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How do you multiply mixed numbers with fractions?
Alex777 [14]

Answer:

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7 0
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Find the equation of the tangent line to the curve (a lemniscate)
olya-2409 [2.1K]

Answer:

m=\frac{9}{13} and b=\frac{40}{13}

Step-by-step explanation:

The equation of curve is

2(x^2+y^2)^2=25(x^2-y^2)

We need to find the equation of the tangent line to the curve at the point (-3, 1).

Differentiate with respect to x.

2[2(x^2+y^2)\frac{d}{dx}(x^2+y^2)]=25(2x-2y\frac{dy}{dx})

4(x^2+y^2)(2x+2y\frac{dy}{dx})=25(2x-2y\frac{dy}{dx})

The point of tangency is (-3,1). It means the slope of tangent is \frac{dy}{dx}_{(-3,1)}.

Substitute x=-3 and y=1 in the above equation.

4((-3)^2+(1)^2)(2(-3)+2(1)\frac{dy}{dx})=25(2(-3)-2(1)\frac{dy}{dx})

40(-6+2\frac{dy}{dx})=25(-6-2\frac{dy}{dx})

-240+80\frac{dy}{dx})=-150-50\frac{dy}{dx}

80\frac{dy}{dx}+50\frac{dy}{dx}=-150+240

130\frac{dy}{dx}=90

Divide both sides by 130.

\frac{dy}{dx}=\frac{9}{13}

If a line passes through a points (x_1,y_1) with slope m, then the point slope form of the line is

y-y_1=m(x-x_1)

The slope of tangent line is \frac{9}{13} and it passes through the point (-3,1). So, the equation of tangent is

y-1=\frac{9}{13}(x-(-3))

y-1=\frac{9}{13}(x)+\frac{27}{13}

Add 1 on both sides.

y=\frac{9}{13}(x)+\frac{27}{13}+1

y=\frac{9}{13}(x)+\frac{40}{13}

Therefore, m=\frac{9}{13} and b=\frac{40}{13}.

5 0
3 years ago
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olga2289 [7]
(3x-5)(2x-7)
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Answer:

2.37 its a rational number because its a decimal

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