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olga2289 [7]
3 years ago
9

Write the equation of the line that is parallel to x – 3y = 9 and passes

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0

Answer:

x – 3y = 9 ⇔ y = \frac{1}{3} x + 3

the line parallel is y' = \frac{1}{3}x + b (b\neq 3)

y' = \frac{1}{3}x + b (b\neq 3) passes through (3, -1) --> -1 = \frac{1}{3} × 3 + b --> b = -2

⇒ y' = \frac{1}{3} x - 2

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We use a^2 - b^2 = (a+b)(a-b)

so x^2 - 4^2 = (x+4)(x-4)

Replace it in the given equation

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we have (x-4)  and (x+4) in the denominator

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subtract 4 onboth side

so x= -4

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