I hope this helps you
5×(3-2)=5×1=5
or
5×(3+(-2))
5×3+5×(-2)
15+(-10)=15-10=5
Answer:
A
Step-by-step explanation:
![f(x) = 20 {e}^{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%2020%20%7Be%7D%5E%7Bx%7D%20)
The exact position of points on a graph! usually using values :)
Answer:
B
Step-by-step explanation:
This is a quadratic in cosines
Factor by considering the factors of the product 2 × 1 = 2 which sum to give the coefficient of the cos x term (3 )
the factors are + 2 and + 1
use these factors to split the middle term
2cos²x + 2cosx + cosx + 1 = 0 (factor by grouping )
2cosx(cosx + 1) + 1(cosx + 1) = 0 (take out common factor (cosx + 1) )
(cosx + 1)(2cosx + 1) = 0
equate each factor to zero and solve for x
cosx + 1 = 0
cosx = - 1 ⇒ x = π
2cosx + 1 = 0
cosx = - ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
since cosx < 0 then x is in second/ third quadrant
x =
or x = ![\frac{4\pi }{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%5Cpi%20%7D%7B3%7D)
Answer:
y = x - 7
Step-by-step explanation:
Parallel lines have the same gradient in this case 1 is the gradient.
Using the point (8,1) we can form our own equation.
1 will be y, 1 will be m, 8 will be x
All we have to do is find C in order to form the equation <em>y</em><em>=</em><em>mx</em><em>+</em><em>c</em>
1 = 1(8) + c
1 = 8 + c
C = - 7
Therefore;
<u>y = x - 7</u>