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3 years ago

I need to study for a test tomorrow and I got these questions online can anyone please tell me the answers.

Mathematics

1 answer:

puteri [66]3 years ago

7 0

1) 4x+6= 10; x=1
2) c + 5= 15; c=10
3) 2 - a= 18; a= -16
4) -8x=16; x= -2
5) a+6= 12; a=6
6) 3+b= 18; b=6
7) -5 - x= 19; x= -24
8) 7+4b= 34; b= 6.75

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During the 2015-16 NBA season, J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 . Assume th

ser-zykov [4K]

Answer: 0.5898

Step-by-step explanation:

Given : J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 .

We assume that,

The probability that .J. Redick makes any given free throw =0.901 (1)

Free throws are independent.

So it is a binomial distribution .

Using binomial probability formula, the probability of getting success in x trials :

$P(X=x)^nC_xp^x(1-p)^{n-x}$

, where n= total trials

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Let x be binomial variable that represents the number of a=makes.

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p= 0.901 (from (1))

The probability that he makes at least 13 of them will be :-

$P(x\geq13)=P(x=13)+P(x=14)$

$=^{14}C_{13}(0.901)^{13}(1-0.901)^1+^{14}C_{14}(0.901)^{14}(1-0.901)^0\\\\=(14)(0.901)^{13}(0.099)+(1)(0.901)^{14}\ \ [\because\ ^nC_n=1\ \&\ ^nC_{n-1}=n ]\\\\\approx0.3574+0.2324=0.5898$

∴ The required probability = 0.5898

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Step-by-step explanation:

Hope It helps!

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