Definition:
a number consisting of an integer and a proper fraction.
Let's put it in our own words!
A number that contains a proper fraction and an integer.
Example: 2 1/3
Hope this helps!
- Melanie
Answer:
(a) ![P(Y'|M)\approx 0.3297](https://tex.z-dn.net/?f=P%28Y%27%7CM%29%5Capprox%200.3297)
(b) ![P(Y|M')\approx 0.8323](https://tex.z-dn.net/?f=P%28Y%7CM%27%29%5Capprox%200.8323)
(c) ![P(Y'|M')\approx 0.1323](https://tex.z-dn.net/?f=P%28Y%27%7CM%27%29%5Capprox%200.1323)
Step-by-step explanation:
Given table is
Yes No Don't Know Total
Men 162 92 25 279
Women 258 41 11 310
Total 420 133 36 589
According the the conditional probability, if A and B are two event then
![P(A|B)=P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}](https://tex.z-dn.net/?f=P%28A%7CB%29%3DP%28%5Cfrac%7BA%7D%7BB%7D%29%3D%5Cfrac%7BP%28A%5Ccap%20B%29%7D%7BP%28B%29%7D)
We need to find the following probabilities.
Let Y is the event "saying yes," and M is the event "being a man."
(a)
![P(Y'|M)=\frac{P(Y'\cap M)}{P(M)}](https://tex.z-dn.net/?f=P%28Y%27%7CM%29%3D%5Cfrac%7BP%28Y%27%5Ccap%20M%29%7D%7BP%28M%29%7D)
![P(Y'|M)=\frac{\frac{92}{589}}{\frac{279}{589}}](https://tex.z-dn.net/?f=P%28Y%27%7CM%29%3D%5Cfrac%7B%5Cfrac%7B92%7D%7B589%7D%7D%7B%5Cfrac%7B279%7D%7B589%7D%7D)
![P(Y'|M)=\frac{92}{279}](https://tex.z-dn.net/?f=P%28Y%27%7CM%29%3D%5Cfrac%7B92%7D%7B279%7D)
![P(Y'|M)=0.329749103943](https://tex.z-dn.net/?f=P%28Y%27%7CM%29%3D0.329749103943)
![P(Y'|M)\approx 0.3297](https://tex.z-dn.net/?f=P%28Y%27%7CM%29%5Capprox%200.3297)
(b)
![P(Y|M')=\frac{P(Y\cap M')}{P(M')}](https://tex.z-dn.net/?f=P%28Y%7CM%27%29%3D%5Cfrac%7BP%28Y%5Ccap%20M%27%29%7D%7BP%28M%27%29%7D)
![P(Y|M')=\frac{\frac{258}{589}}{\frac{310}{589}}](https://tex.z-dn.net/?f=P%28Y%7CM%27%29%3D%5Cfrac%7B%5Cfrac%7B258%7D%7B589%7D%7D%7B%5Cfrac%7B310%7D%7B589%7D%7D)
![P(Y|M')=\frac{258}{310}](https://tex.z-dn.net/?f=P%28Y%7CM%27%29%3D%5Cfrac%7B258%7D%7B310%7D)
![P(Y|M')=0.832258064516](https://tex.z-dn.net/?f=P%28Y%7CM%27%29%3D0.832258064516)
![P(Y|M')\approx 0.8323](https://tex.z-dn.net/?f=P%28Y%7CM%27%29%5Capprox%200.8323)
(c)
![P(Y'|M')=\frac{P(Y'\cap M')}{P(M')}](https://tex.z-dn.net/?f=P%28Y%27%7CM%27%29%3D%5Cfrac%7BP%28Y%27%5Ccap%20M%27%29%7D%7BP%28M%27%29%7D)
![P(Y'|M')=\frac{\frac{41}{589}}{\frac{310}{589}}](https://tex.z-dn.net/?f=P%28Y%27%7CM%27%29%3D%5Cfrac%7B%5Cfrac%7B41%7D%7B589%7D%7D%7B%5Cfrac%7B310%7D%7B589%7D%7D)
![P(Y'|M')=\frac{41}{310}](https://tex.z-dn.net/?f=P%28Y%27%7CM%27%29%3D%5Cfrac%7B41%7D%7B310%7D)
![P(Y'|M')=0.132258064516](https://tex.z-dn.net/?f=P%28Y%27%7CM%27%29%3D0.132258064516)
![P(Y'|M')\approx 0.1323](https://tex.z-dn.net/?f=P%28Y%27%7CM%27%29%5Capprox%200.1323)
<u><em>9 is the greatest common factor correct answer.</em></u> First you had to find prime factorization of 9: 1, 3, 9, 3²=3*3=9. And then, you had to find prime factorization of 27: 1, 3, 9, 27, 3³=3*3*3=27. The greatest common factor of 9 and 27 is 9 is the final answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie
Answer: 0.2
Step-by-step explanation: Necesitamos ajustar la estimación de 0.1561 al décimo más cercano.
El número después del decimal es el número en el décimo lugar. Considere el número a un lado del lugar de las décimas y utilice el número para decidir si se reunirán o seguirán siendo el equivalente. Observe que el número a un lado del décimo lugar es mayor o equivalente a 5 o menos de 5. En el caso de que ese número sea más digno de mención o equivalente a 5, en ese punto el número se reunirá aún en la remota posibilidad de que ese número es menor de 5, en ese momento el número no se reunirá. Permanecerá igual.
Consideremos el número dado 0.1561
El número en el lugar de las décimas es 1
El número después del punto de las décimas es 5 (que es más prominente o equivalente a 5)
De esta manera, el número se reunirá en 0,2
Answer:
y=8
Step-by-step explanation:
if y = -x +7
then
y= 1 + 7 cause we know x = -1 so negative x is 1
so 1+7=8
so y = 8
hope this helped :)