Given:
A line passes through (1,-2) and is perpendicular to 
.
To find:
The equation of that line.
Solution:
We have, equation of perpendicular line.
Slope of this line is
Product of slope of two perpendicular lines is -1.
Now, slope of required line is 
and it passes through (1,-2). So, the equation of line is
where, m is slope.
Therefore, the equation of required line is .
By using the midpoint formula and the equation of the line, the equation of the line of symmetry is x = - 2.
<h3>How to derive the equation of the axis of symmetry </h3>
In this question we know the locations of two points with the same y-value, which means that the axis of symmetry is parallel to the y-axis and that both points are equidistant. Thus, the axis of symmetry passes through the midpoint of the line segment whose ends are those points.
First, calculate the coordinates of the midpoint by the midpoint formula:
M(x, y) = 0.5 · (- 7, 11) + 0.5 · (3, 11)
M(x, y) = (- 2, 11)
Second, look for the first coordinate of the midpoint and derive the equation of the line associated with the axis of symmetry:
x = - 2
By using the midpoint formula and the equation of the line, the equation of the line of symmetry is x = - 2.
To learn more on axes of symmetry: brainly.com/question/11957987
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Yes, it is possible. For example, let's say that point A is (0,4) and there's a reflection over the y-axis, then point A would still be (0,4).
