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Mrrafil [7]
4 years ago
12

Find the arc length, x, when r= 8 and 0 = 5 radians.

Mathematics
1 answer:
lys-0071 [83]4 years ago
7 0

Answer:

Arc Length = 40

Step-by-step explanation:

Arc Length Formula:  S = rΘ

R = radius

Θ = Radians

<u>Step 1:  Identify the radius and the radian angle</u>

R = 8

Θ = 5 radians

<u>Step 2:  Plug into the equation</u>

S = (8)(5)

<u>Step 3:  Solve</u>

S = 40

Answer:  Arc Length = 40

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mihalych1998 [28]

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~~~

If a paper is 4/1000 inches think, how many of them will it take to equal 1000?

Well... if we take 1000 divided by 4 we get 250.

So 250 sheets of paper would be 1 inch thick...

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nikdorinn [45]

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If 1550 students voted but there were only 2000 eligible voters what percent of students voted
AURORKA [14]
To get that percentage you just need to divide 1550 by 200p:
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6 0
3 years ago
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y
kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69  104  125  129  60  64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

  • M is the sample mean weight of the wild mountain lions (\frac{69 +104 +125 +129+60 +64}{6} =91.8)
  • ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
  • s is the standard deviation of the sample(31.4)
  • N is the sample size (6)

Thus, ME=\frac{1.30*31.4}{\sqrt{6} } ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0
3 years ago
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