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3 years ago

Find the arc length, x, when r= 8 and 0 = 5 radians.

Mathematics

1 answer:

lys-0071 [83]3 years ago

7 0

Answer:

Arc Length = 40

Step-by-step explanation:

Arc Length Formula: S = rΘ

R = radius

Θ = Radians

Step 1: Identify the radius and the radian angle

R = 8

Θ = 5 radians

Step 2: Plug into the equation

S = (8)(5)

Step 3: Solve

S = 40

Answer: Arc Length = 40

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Answer:

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Step-by-step explanation:

I just did the work myself and even ran it through a calculator but the correct answer isn't one of those options. Here's my work:

$-\frac{5}{6} =z+\frac{1}{8}\\-\frac{5}{8}-\frac{1}{8}=z\\-\frac{40}{48}-\frac{6}{48}=z\\-\frac{46}{48}=z\\-\frac{23}{24}$

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2 years ago

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sweet [91]

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Let t as y² + 5y .

${y}^{2} + 5y = t$

Rewrite the equation :

$t - \frac{36}{t} = 0 \\$

Multiply sides by t

$t \times (t - \frac{36}{t} ) = t \times 0 \\$

${t}^{2} - 36 = 0$

Add sides 36

${t}^{2} - 36 + 36 = 0 + 36$

${t}^{2} = 36$

$t = ± \: 6$

_________________________________

So :

${y}^{2} + 5y = 6$

Subtract sides 6

${y}^{2} + 5y - 6 = 6 - 6$

${y}^{2} + 5y - 6 = 0$

$(y + 6)(y - 1) = 0$

$y = - 6 \: \: or \: \: y = 1$

##############################

${y}^{2} +5y = - 6$

$No \: \: solution$

_________________________________

Thus (( y = 1 )) and (( y = - 6 )) are the roots of the equation .

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3 years ago

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Whitepunk [10]

Answer:

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Step-by-step explanation:

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This is the middle between 18 and 21.

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