All categories

3 years ago

What is the value of x? Enter your answer in the box. x =

Mathematics

1 answer:

lukranit [14]3 years ago

5 0

Answer:

x = 24

Step-by-step explanation:

To find the value of x, create a proportion. A proportion is two equal ratios for similar figures. The two triangles are similar because they are the same shape but not the same size. Create ratios between corresponding sides of figures.

$\frac{44.8}{x+4}=\frac{56}{35}$

To solve for x, cross multiply:

44.8(35) = (x+4)(56)

1568 = 56x + 224

1344 = 56x

24 = x

You might be interested in

Find the area of the shaded region to the nearest tenth. See picture for full problem. Please and thank you so much!

Anestetic [448]

Answer:

Step-by-step explanation:

Radius =6 ft

Area of circle = πr²

= 3.14 * 6 * 6

= 113.04 ft²

base = 10.39 ft

height = 6+3 = 9 ft

$Area \ of \ triangle = \dfrac{1}{2}*base * height\\\\\\=\dfrac{1}{2}*10.39*9\\$

= 46.76 ft²

Area of the shaded region = area of circle - area of triangle

= 113.04 - 46.76

= 66.28

= 66.3 ft²

8 0

2 years ago

Find an ordered pair (x, y) that is a solution to the equation. 5x-y=5 (x, y) = ?

Sonja [21]

Hi there!

There are multiple solutions to your question. Some possible solutions could be the following:
(0, -5)
(1, 0)
(2, 5)

8 0

3 years ago

Write an equation for a quadratic function that has x intercepts (-3, 0) and (5, 0)

Blizzard [7]

Answer:

One possible equation is $f(x) = (x + 3)\, (x - 5)$ , which is equivalent to $f(x) = x^{2} - 2\, x - 15$ .

Step-by-step explanation:

The factor theorem states that if $x = x_{0}$ (where $x_{0}$ is a constant) is a root of a function, $(x - x_{0})$ would be a factor of that function.

The question states that $(-3,\, 0)$ and $(5,\, 0)$ are $x$ -intercepts of this function. In other words, $x = -3$ and $x = 5$ would both set the value of this quadratic function to $0$ . Thus, $x = -3\!$ and $x = 5\!$ would be two roots of this function.

By the factor theorem, $(x - (-3))$ and $(x - 5)$ would be two factors of this function.

Because the function in this question is quadratic, $(x - (-3))$ and $(x - 5)$ would be the only two factors of this function. In other words, for some constant $a$ ( $a \ne 0$ ):

$f(x) = a\, (x - (-3))\, (x - 5)$ .

Simplify to obtain:

$f(x) = a\, (x + 3)\, (x - 5)$ .

Expand this expression to obtain:

$f(x) = a\, (x^{2} - 2\, x - 15)$ .

(Quadratic functions are polynomials of degree two. If this function has any factor other than $(x - (-3))$ and $(x - 5)$ , expanding the expression would give a polynomial of degree at least three- not quadratic.)

Every non-zero value of $a$ corresponds to a distinct quadratic function with $x$ -intercepts $(-3,\, 0)$ and $(5,\, 0)$ . For example, with $a = 1$ :