Question

HELP EMERGENCY, I'll give brainiest

Answer 1

-1/2d + 3/8 - d = 1/4 + 3/4d +2

First combine like terms on both sides:

-1 1/2d + 3/8 = 2 1/4 + 3/4d

Add 1 1/2d to both sides:

3/8 = 2 1/4 + 2 1/4d

Subtract 2 1/4 from both sides:

-1 7/8 = 2 1/4d

Divide both sides by 2 1/4:

d = -5/6

Answer 2

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

• $\tt- \frac{ 1 }{ 2 } d+ \frac{ 3 }{ 8 } -d = \frac{ 1 }{ 4 } + \frac{ 3 }{ 4 } d+2$

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\tt- \frac{ 1 }{ 2 } d+ \frac{ 3 }{ 8 } -d = \frac{ 1 }{ 4 } + \frac{ 3 }{ 4 } d+2$

Combine $\tt-\frac{1}{2}d$ and -d to get $\tt-\frac{3}{2}d$.

$\tt-\frac{3}{2}d+\frac{3}{8}=\frac{1}{4}+\frac{3}{4}d+2$

Because 1/4 and 8/4 have the same denominator, add them by adding their numerators.

$\tt-\frac{3}{2}d+\frac{3}{8}=\frac{1+8}{4}+\frac{3}{4}d$

Subtract $\tt\frac{3}{4}d$ from both sides.

$\tt-\frac{3}{2}d+\frac{3}{8}-\frac{3}{4}d=\frac{9}{4}$

Combine $\tt-\frac{3}{2}d$ and $\tt-\frac{3}{4}d$ to get $\tt-\frac{9}{4}d$.

$\tt-\frac{9}{4}d+\frac{3}{8}=\frac{9}{4}$

Subtract 3/8 from both sides.

$\tt-\frac{9}{4}d=\frac{9}{4}-\frac{3}{8}$

The least common multiple of 4 and 8 is 8. Convert 9/4 and 3/8 to fractions with denominator 8.

$\tt-\frac{9}{4}d=\frac{18}{8}-\frac{3}{8}$

Because 18/8 and 3/8 have the same denominator, subtract them by subtracting their numerators.

$\tt-\frac{9}{4}d=\frac{18-3}{8}$

Subtract 3 from 18 to get 15.

$\tt-\frac{9}{4}d=\frac{15}{8}$

Multiply both sides by - 4/9, the reciprocal of -9/4.

$\tt \: d=\frac{15}{8}\left(-\frac{4}{9}\right)$

Multiply 15/8 by -4/9 by multiplying the numerator by the numerator and the denominator by the denominator.

$\tt \: d=\frac{15\left(-4\right)}{8\times 9}$

Carry out the multiplications in the fraction ⇨ $\tt\frac{15\left(-4\right)}{8\times 9}$.

$\tt \: d=\frac{-60}{72}$

Reduce the fraction -60/72 to its lowest terms by extracting and cancelling out 12.

$\boxed{ \boxed{ \bf \: d=-\frac{5}{6}\approx -0.833..}}$