The required probability of the coin landing tails up at least two times is 15/16.
Given that,
A fair coin is flipped seven times. what is the probability of the coin landing tails up at least two times is to be determined.
<h3>What is probability?</h3>
Probability can be defined as the ratio of favorable outcomes to the total number of events.
Here,
In the given question,
let's approach inverse operation,
The probability of all tails = 1 / 2^7 because there is only one way to flip these coins and get no heads.
The probability of getting 1 head = 7 /2^7
Adding both the probability = 8 / 2^7
Probability of the coin landing tails up at least two times = 1 - 8/2^7
= 1 - 8 / 128
= 120 / 128
= 15 / 16
Thus, the required probability of the coin landing tails up at least two times is 15/16.
Learn more about probability here:
brainly.com/question/14290572
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Answer:
Step-by-step explanation:
4x+2y = -24 -------------(i)
<u> -4x+y = 12 -</u>------------(ii)
add (i) &(ii) 3y = -12
y = -12/3
y = -4
Put y = (-4) in (i)
4x + 2*(-4) = -24
4x - 8 = -24
4x = -24 + 8
4x = -16
x = -16/4
x = -4
Answer:
$17.45
Step-by-step explanation:
$17.45*3=52.35
$52.35+$45.99=$98.34
