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Vlad [161]
3 years ago
14

Write the standard form of the equation of a line if the point on the line nearest to the origin is at (6, 8).

Mathematics
1 answer:
Alchen [17]3 years ago
4 0

Answer:

\large\boxed{y=\dfrac{4}{3}x}

Step-by-step explanation:

The line passes through the origin has an equation y = mx

m - slope

The formula of a slope of a line passes through the origin

and a point (x, y):

m=\dfrac{y}{x}

We have the point (6, 8). Substitute:

m=\dfrac{8}{6}=\dfrac{8:2}{6:2}=\dfrac{4}{3}

Finally:

y=\dfrac{4}{3}x

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Factorise this expression as fully as possible<br> 4x^2+x^3
gtnhenbr [62]

Answer:

x^2(4+x)

Step-by-step explanation:

you have to factor out x^2 off both equations since that's the only thing that you can divide off the equations

4 0
4 years ago
Help please it says round your answer to the nearest hundredth
Snowcat [4.5K]

Answer:

∠ B ≈ 62.73°

Step-by-step explanation:

Using the sine ratio in the right triangle.

sinB = \frac{opposite}{hypotenuse} = \frac{AC}{AB} = \frac{8}{9} , thus

∠ B = sin^{-1} (\frac{8}{9} ) ≈ 62.73° ( to the nearest hundredth )

6 0
3 years ago
A paper reported that in a representative sample of 282 American teens age 16 to 17, there were 71 who indicated that they had s
elena-s [515]

Answer:

z=\frac{0.252 -0.25}{\sqrt{\frac{0.25(1-0.25)}{282}}}=0.0776  

p_v =P(z>0.0776)=0.4691  

Since the p value is higher than the significance level so then we can conclude that we have enough evidence to FAIL to reject the null hypothesis and there is no evidence in order to say that the true proportion of teens more than a quarter of Americans age 16 to 17 have sent a text message while driving is higher than 0.25

Step-by-step explanation:

Information provided

n=282 represent the sample selected

X=71 represent the teens indicated that they had sent a text message while driving

\hat p=\frac{71}{282}=0.252 estimated proportion of teens indicated that they had sent a text message while driving

p_o=0.25 is the value that we want to test

\alpha=0.01 represent the significance level

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to check if more than a quarter of Americans age 16 to 17 have sent a text message while driving, and the hypothesis are:

Null hypothesis:p\leq 0.7  

Alternative hypothesis:p > 0.25  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.252 -0.25}{\sqrt{\frac{0.25(1-0.25)}{282}}}=0.0776  

Decision

The p value for this case is:

p_v =P(z>0.0776)=0.4691  

Since the p value is higher than the significance level so then we can conclude that we have enough evidence to FAIL to reject the null hypothesis and there is no evidence in order to say that the true proportion of teens more than a quarter of Americans age 16 to 17 have sent a text message while driving is higher than 0.25

8 0
3 years ago
Jennifer has $3955 in her retirement account, and Reggie has $3935 in his. Jennifer is adding
olga nikolaevna [1]

Answer:

3955, 3963, 3971,

that's jennifer's

3935, 3953, 3971,

that's Reggie's

so Jennifer would have 3971 on the third day, and so would reggie. the amount would be 3971

4 0
3 years ago
Hey guys, I will award brainliest for anyone who answers this? ​
yaroslaw [1]

Answer:

- 15/-5 + (-2)²

3+4=7.

Jsjsuwa

8 0
3 years ago
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