If sinA=a_1/a+1 find value of tanA

C = 0.20m+2.00 what is the charge for 2.7 mile ride?

svetoff [14.1K]

M = number of miles
m = 2.7 is plugged into the equation to get
C = 0.20*m + 2.00
C = 0.20*2.7 + 2.00
C = 0.54 + 2.00
C = 2.54
The cost is $2.54

3 0

3 years ago

How to find factors of any numbers?

JulijaS [17]

Answer:Find all the numbers less than or equal to the given number.

Divide the given number by each of the numbers.

The divisors that give the remainder to be 0 are the factors of the number.

Step-by-step explanation:Find all the numbers less than or equal to the given number.

Divide the given number by each of the numbers.

The divisors that give the remainder to be 0 are the factors of the number.

3 0

2 years ago

What equation can be used to find the length of AC

Leno4ka [110]

I'm pretty sure this is the answer:
(10)sin(40°) = AC

It's sin becasue it needs the opposite side of 40° and has the hypotenuse.

5 0

3 years ago

Find the differential coefficient of <img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^

Gemiola [76]

Answer:

$\rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x}$

Step-by-step explanation:

we would like to figure out the differential coefficient of $e^{2x}(1+\ln(x))$

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

$\displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )$

to do so distribute:

$\displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x}$

take derivative in both sides which yields:

$\displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )$

by sum derivation rule we acquire:

$\rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x}$

Part-A: differentiating $e^{2x}$

$\displaystyle \frac{d}{dx} {e}^{2x}$

the rule of composite function derivation is given by:

$\rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)$

so let g(x) [2x] be u and transform it:

$\displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x$

differentiate:

$\displaystyle {e}^{u} \cdot 2$

substitute back:

$\displaystyle \boxed{2{e}^{2x} }$

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

$\displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)$

let

$f(x) \implies \ln(x)$
$g(x) \implies {e}^{2x}$

substitute

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x}$

differentiate:

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }$

Final part:

substitute what we got:

$\rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }$

and we're done!

6 0

3 years ago

A motorcycle can travel 15 miles on 3/8 of a gallon of gasoline. Find the unit rate in miles per gallon

yaroslaw [1]

Answer:

40 mpg

Step-by-step explanation:

To find the unit rate which is 1/8 we just divide 15 by 3 which is 5 and to find the mpg of the full gallon now that we have the unit rate we just multiply the 1/8 or 5 miles by 8 which would give us 8/8 or 40 miles.

3 0

2 years ago

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If sinA=a_1/a+1 find value of tanA​

If sinA=a_1/a+1 find value of tanA