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AlekseyPX
3 years ago
8

Can someone help me please

Mathematics
2 answers:
statuscvo [17]3 years ago
8 0

Answer:

21

Step-by-step explanation:

I added them together, first the 9-10 year olds and the 11-12 year olds. There were 15, then added on the 13-14 ear olds, making altogether 21 kids over the age of 8

mojhsa [17]3 years ago
3 0

Answer:

Your answer is B

Step-by-step explanation:

There are 3 kids ages 9-10, so that's the first 3.

There are 10 kids ages 10-11, so that's the second 10.

There are 6 kids ages 11-12, so that's the third 6.

add those kids up and you get 19

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Let's define the following variables first.

A = number of tickets sold for adults

C = number of tickets sold for children

From the question, we can say that or form the following equations:

1. A + C = 790 tickets

2. $7A + $4C = $4, 390

The first equation can also be written as A = 790 - C. We can use this equation and replace "A" in the second equation.

7(790-C)+4c=4,390

From that, we can solve "C" by solving the equation formed above.

\begin{gathered} \text{Distribute 7 to the terms inside the parenthesis.} \\ 7(790)-7(C)+4C=4,390 \\ 5,530-7C+4C=4,390 \\ \text{Subtract 5,530 on both sides of the equation.} \\ -7C+4C=-1140 \\ -3C=-1140 \\ \text{Divide -3 on both sides.} \\ C=380 \end{gathered}

Therefore, 380 tickets for children were sold.

Since there are 790 tickets in total that are sold and 380 tickets for children were sold, we can say that 410 tickets for adult was sold.

\begin{gathered} A=790-C \\ A=790-380 \\ A=410 \end{gathered}

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10 months ago
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