Answer:
E
Step-by-step explanation:
Perimeter =5s+5s+2s+2s+0.75+0.75
2 off each implies part E
Answer:
- Question 1a. i)

- Question 1a. ii)

- Question 1b)

Explanation:
<u><em>Question 1 a. i) Find the value of x.</em></u>

For the smalll triangle you can write:

For tthe big triangle:

Substitute:

Solve for x:

<u><em>Question 1a ii) Find the volume of the frustrum</em></u>
- Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m
Formula:

Substitute:

- Find the volume of a cone with heigth = 1.8m and radius = 1m

- Subtract the volume of the small cone from the volume of the big cone

<u><em>Question 1b. Calculate the volume of the bin</em></u>
<u>i) Upper frustrum</u>
This is the same frustrum from the equation of above, thus ist volume is 27.6m³.
<u>ii) Lower frustrum</u>




<u>iii) Add the volume of the two frustrums</u>
Answer:
Third option
Step-by-step explanation:
Because it has to be JKL or LKJ, (see how the K stays in the middle)
I really don't know what you mean, but to find the percent, multiply x and y and then divide your answer by 100, or move your decimal place to the left twice. hope that helped :)