598.61 rounded to the nearest tenth is 598.60 I got the answer by rounding ;P

jk

You just have to look at the tenths place (the place your rounding to) which is .6 The look to the number next to it on the right (.01) If that number on the right is 4 or less, the number youre rounding to stays the same (but all the numbers to the right of it turn into zeros.) If the number to the right is 5 or more, than add 1 to the number your rounding to. But here the number to the right is less than 4 so the answer is 598.60.

6 0

3 years ago

Enter the missing exponent.

konstantin123 [22]

Answer:

The missing exponent is 20.

Step-by-step explanation:

$y^{29} / y^{20} = y^9$

upper exponent minus lower exponent.

4 0

3 years ago

What is the answer to the system of equations problem 3x=2y+10 9y=3x-7

Gemiola [76]

Solving:

$\left \{ {{3x = 2y + 10} \atop {9y = 3x-7}} \right.$
Organize by putting the unknowns left and right the numbers without letter, changing the signal when changing sides.
 $\left \{ {{3x-2y=10\:(I)} \atop {-3x+9y=-7\:(II)}} \right.$
Eliminate opposites (+ 3x and -3x)
 $\left \{ {{\diagup\!\!\!\!3x-2y=10} \atop {-\diagup\!\!\!\!3x+9y=-7}} \right.$
$\left \{ {{-2y=10} \atop {9y=-7}} \right.$
----------------------------
$7y = 3$
$\boxed{y = \frac{3}{7} }$

Now substitute the found value "y" in the first equation:
 $3x-2y=10\:(I)$
$3x-2* \frac{3}{7} =10$
$3x- \frac{6}{7} = 10$
$\frac{21x}{\diagup\!\!\!\!7} - \frac{6}{\diagup\!\!\!\!7} = \frac{70}{\diagup\!\!\!\!7}$
$21x - 6 = 70$
$21x = 70 + 6$
$21x = 76$
$\boxed{x = \frac{76}{21} }$

Answer:
$(x,y) = ( \frac{76}{21} , \frac{3}{7} )\end{array}}\qquad\quad\checkmark$


Taking the truth proof

$3x - 2y = 10\:(I)$
$3* \frac{76}{21} - 2* \frac{3}{7} = 10$
$\frac{228}{21} - \frac{6}{7} = 10$
$\frac{1596-126}{147} = 10$
$\frac{1470}{147} = 10$
$10 = 10\:(TRUE)$

8 0

3 years ago

Hiep is writing a coordinate proof to show that the midsegment of a trapezoid is parallel to its bases. He starts by assigning c

bagirrra123 [75]

Answer:

Step-by-step explanation:

Given that KLMN is a trapezium.

K has coordinates (0,0), L(2a,0), M(2d,2c) and N(2b,2c)

R is the mid point of KN

Hence coordinates of R will be using mid point formula (x1+x2/2, y1+y2/2)

= (a,c)

Similarly S is mid point of segment LM.

Hence S = (a+d,c)

The slope of SL is = (y2-y1)/(x2-x1) = (a-d)/-c=(d-a)/c

The slope of RS = (c-c)/d =0

The slope of NM = (2c-2c)/(2b-2d) = 0

Since slope of RS = slope of NM

We get RS is parallel to NM

Already NM is parallel to KL because bases of trapezium

Hence RS is parallel to both the bases.

7 0

3 years ago