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2 years ago

10

3 3/4 / 2/5 = what? I'm struggling

1 answer:

Soloha48 [4]2 years ago

3 0

Lets convert 3 3/4 into improper fraction first.

$3\frac{3}{4} = \frac{3 \times 4 + 3}{4} \\ = \frac{15}{4}$

$\frac{3\frac{3}{4} }{ \frac{2}{5} } \\ = \frac{15}{4} \div \frac{2}{5} \\ = \frac{15}{4} \times \frac{5}{2} \\ = \frac{75}{6} \\ = \frac{25}{2} \: or12 \frac{1}{2} or \: 12.5$

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Write the equation of the line passing through the points (-7,8) and (7,2) The equation of the line is [ ]Can someone please hel

Natalka [10]

Answer:

y = -3/7x + 5

Step-by-step explanation:

y2 - y1 / x2 - x1

2 - 8 / 7 - (-7)

-6/14

= -3/7

y = -3/7x + b

2 = -3/7(7) + b

2 = -3 + b

5 = b

6 0

2 years ago

What is the perimeter of the triangle shown on the coordinate plane,to the nearest tenth of a unit ?

ollegr [7]

Answer:

25.6 units

Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

$d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}$

where

$(x_1,y_1)$ are the coordinates of the first point

$(x_2,y_2)$ are the coordinates of the second point

- For AB:

$d=\sqrt{[1-(-5)]^{2}+(4-4)^2}$

$d=\sqrt{(1+5)^{2}+(0)^2}$

$d=\sqrt{(6)^{2}}$

$d=6$

- For BC:

$d=\sqrt{(3-1)^{2} +(-4-4)^{2}}$

$d=\sqrt{(2)^{2} +(-8)^{2}}$

$d=\sqrt{4+64}$

$d=\sqrt{68}$

$d=8.24$

- For AC:

$d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}$

$d=\sqrt{(3+5)^{2} +(-8)^{2}}$

$d=\sqrt{(8)^{2} +64}$

$d=\sqrt{64+64}$

$d=\sqrt{128}$

$d=11.31$

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

$p=AB+BC+AC$

$p=6+8.24+11.31$

$p=25.55$

$p=25.6$

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

6 0

3 years ago

What is 9 1/2 - 5 7/12 =

Soloha48 [4]

Answer:

47/12, or 3 11/12

Step-by-step explanation:

9 1/2 - 5 7/12 > convert to improper fractions

19/2 - 67/12

make same denominator (12)

19/2 * 6 = 114/12

114/12 - 67/12 = 47/12

7 0

2 years ago

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2 years ago

Read 2 more answers

Elza [17]

Answer:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

$(e)\ 2(x - 10) = -12$

Step-by-step explanation:

Required

Which equals $x = 4$

$(a)\ 2x + 6 = 2$

Collect like terms

$2x = 2 - 6$

$2x = -4$

Divide both sides by 2

$x = -2$

$(b)\ 2x - 9 = -1$

Collect like terms

$2x = -1 + 9$

$2x = 8$

Divide both sides by 2

$x = 4$

$(c)\ -2x + 12 = 4$

Collect like terms

$-2x =- 12 + 4$

$-2x =-8$

Divide both sides by -2

$x = 4$

$(d)\ 2(x + 2) = 10$

Divide both sides by 2

$x + 2 =5$

Collect like terms

$x = 5-2$

$x = 3$

$(e)\ 2(x - 10) = -12$

Divide both sides by 2

$x - 10 = -6$

Collect like terms

$x = 10 - 6$

$x = 4$

Hence, the equations with the required solution are:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

$(e)\ 2(x - 10) = -12$

3 0

2 years ago