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3 years ago

Kylie starts with $145 in her piggy bank. Each month she addes $20.

Mathematics

2 answers:

GaryK [48]3 years ago

7 0

Answer: a=145 +22=167

Step-by-step explanation:

pochemuha3 years ago

5 0

Answer:

a=145 +20=165

Step-by-step explanation:

if she starts with 145 and adds 20 you would have 165 so it would be D

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How do i solve for <br> (2x/5)+1=13/5

NNADVOKAT [17]

Answer:

x = 4

Step-by-step explanation:

$\frac{2x}{5} +1 = \frac{13}{5}$
$\frac{2x+5}{5} = \frac{13}{5}$ divide both sides by 5
2x + 5 = 13 subtract 5 from both sides
2x = 8 divide both sides by 2
x = 4

5 0

3 years ago

Write the inverse function for the function, ƒ(x) = x + 4. Then, find the value of ƒ -1(4). Type your answers in the box.

KATRIN_1 [288]

F(x)^-1=x-4
f(4)^-1=0

8 0

3 years ago

(x - 6)^2 - 12 = x^2- 12x + c. What is the value of c?

mojhsa [17]

Answer:

C = 24

Step-by-step explanation:

(x - 6)² - 12 = x² - 12x + c

(x - 6) (x - 6) -12 = x² - 12x + c

x(x - 6) - 6(x - 6) - 12 = x² - 12x + c

x² - 6x -6x + 36 - 12 = x² - 12x + c

x² - 12x +36 - 12 = x² - 12x + c

x² - 12x + 24 = x² - 12x + c

24 = c

4 0

2 years ago

WILL MARK BRAINLIEST

il63 [147K]

Answer:

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Step-by-step explanation:

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3 years ago

A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.

AVprozaik [17]

Answer:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

8 0

3 years ago