F(x) = 5x^2-x+9 find the difference quotient hurry!!!
2 answers:
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SA= Lateral Area + Area (of base)
Lateral area = perimeter of base x height
An isosceles triangle has two congruent base segments. The hypotenuse of an isosceles right triangle is (length of base segment) x (the square root of 2). I did the math for you (shown above) to get 5 as a base.
So 5 + 5 + square root of 50 is your perimeter
Multiply the perimeter times your height (8) and you get the lateral area.
Add your lateral area to the base area (triangle = 1/2 bh)
LA = 136.568...
Area of Triangle base = 12.5
Surface area = 149.068... square cm
Lateral area = perimeter of base x height
An isosceles triangle has two congruent base segments. The hypotenuse of an isosceles right triangle is (length of base segment) x (the square root of 2). I did the math for you (shown above) to get 5 as a base.
So 5 + 5 + square root of 50 is your perimeter
Multiply the perimeter times your height (8) and you get the lateral area.
Add your lateral area to the base area (triangle = 1/2 bh)
LA = 136.568...
Area of Triangle base = 12.5
Surface area = 149.068... square cm
Answer: The linear equations intersect at 5 , -4
Answer:
y = -2x - 7
Step-by-step explanation:
x - 2y = 6
-2y = -x + 6
Divide the whole equation by (-2)
slope = 1/2
Slope of the line perpendicular to this line = -1/m = -1 ÷ (1/2)
(-3, - 1)
y -y1 = m(x -x1)
y - [-1] = -2(x - [-3])
y + 1 = -2(x + 3)
y + 1= x* (-2) + 3*(-2)
y + 1 = -2x - 6
y = -2x - 6 - 1
y = -2x - 7