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3 years ago

340 pages; 20% decrease=? (With work plz)

Mathematics

1 answer:

pishuonlain [190]3 years ago

4 0

340 × .2 = 68

68 page decrease

340 - 68 = 272

272 pages left

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Can someone check if this is right please? If not what is the correct way?

Charra [1.4K]

A, B, and C are the coefficients. They are not the terms as you have written now.

A quadratic equation is in the form Ax^2 + Bx + C. Therefore, A = 1, B = 8, and C = -6.

The axis of symmetry is found using the equation -b/2a, as you've done. Therefore, the axis of symmetry is -8/2(1) = -4.

Hope this helps!! :)

6 0

3 years ago

You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the

Otrada [13]

Answer:

Please check the explanation.

Step-by-step explanation:

a) How much will you have at the middle of the first year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

Total amount = A = ?

Using the formula

$A\:=\:P\left(1+\frac{r}{n}\right)^{nt}$

substituting the values

$A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}$

$A=300\cdot \frac{2.06}{2}$

$A=\frac{618}{2}$

$A=309$ $

Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

Total amount = A = ?

Using the formula

$A\:=\:P\left(1+\frac{r}{n}\right)^{nt}$

so substituting the values

$A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}$

$A=300\cdot \frac{2.06^2}{2^2}$

$A=318.27$ $

Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 1 year is $ 318.27.

7 0

3 years ago

Remove the parentheses and simplify 3a^2-6ab+3b^2-5(-6a^2+7ab-7b^2)

Oksi-84 [34.3K]

$3a^2-6ab+3b^2-5(-6a^2+7ab-7b^2)=\\\\3a^2-6ab+3b^2+30a^2-35ab+35b^2=\\\\33a^2-41ab+38b^2$

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3 years ago

-3 (-4) ×<br> 1 = –16<br> The answer babesss!!!!!

zvonat [6]

Answer:

x = -(4/3)

Step-by-step explanation:

$-3 (-4) \times1 = -16\\\\\mathrm{Divide\:both\:sides\:by\:}-3\left(-4\right)\times\:1\\\\\frac{-3\left(-4\right)x\times\:1}{-3\left(-4\right)\times\:1}=\frac{-16}{-3\left(-4\right)\times\:1}\\\\Simplify\\\\x=-\frac{4}{3}$

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3 years ago

Use the grouping method to factor the polynomial below completely.<br> x - 3x² + 5x - 157

Levart [38]

Answer:

-3x^2+6x-157

Step-by-step explanation:

8 0

3 years ago