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jeyben [28]
3 years ago
11

A foundation donates $677 per year to the state university. How much will the foundation donate in total to the university in 34

years?
Mathematics
1 answer:
IceJOKER [234]3 years ago
6 0

Answer:

23018

Step-by-step explanation:

do 677 times the 34 years because it the total amount of money.

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tester [92]
Just an 15% 15.8% to be exact
3 0
3 years ago
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In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
2 years ago
For the pair of supply-and-demand equations, where x represents the quantity demanded in units of 1000 and p is the unit price i
Liono4ka [1.6K]

Answer:

7 and 6 respectively

Step-by-step explanation:

Firstly, we have to solve the equations simultaneously.

2x + 7p = 56

3x - 11p = -45

Multiply equation I by 3 and ii by 2

6x +21p = 168

6x - 22p = -90

Subtract the second from first to yield:

43p = 258

p = 6

Insert this in equation 1 where we have 2x + 7p = 56

2x + 7(6) =56

2x + 42 = 56

2x = 14 and x = 7

The equilibrium price is 6 and the equilibrium quantity is 7

8 0
3 years ago
The tennis club where you play tennis charges $50.00 per month and $10.00 per hour of court time. If your current month's bill i
anyanavicka [17]

Answer:

Option B. 5 hours

Step-by-step explanation:

The tennis club charges monthly fees = $50.00

and per hour charges of court time = $10.00

Lets assume you play number of hours in a month = x hr

So, per hour charges would be = $10x

Total payment = monthly charges + charges of played hours

$100.00 = $50.00 + 10x

10x = 100 - 50

10x = 50

x = 5

Option B. You used 5 hours court time.

7 0
2 years ago
Can someone help me please
Llana [10]

Answer:

8: 50 hours

9: 6 inches

10: 43 cm

Step-by-step explanation:

I couldn't see the entirety of 7 because some of the page was folded, so I didn't answer it.

8: Make them equations of y=12x+450 and y=21x. Since both equal y, set them equal to each other so 21x=12x+450. Subtract 12x from both sides to get 9x=450. Divide by 9 on both sides to get 50.

9: The length equals 3w-6 and the width is just w. The perimeter would equal 2w+2(3w-6) which when factored is 2w+6w-12. Simplify to 8w-12. If P=8w-12 and we know P=36, then set the two equations equal to each other so that 8w-12=36. Add 12 to both sides to get 8w=48. Then divide both sides by 8 to get a final answer of w=6.

10. P=x+5x+8+4x-7. Simplify that to P=10x+1. We know that P=71, so set the two equations equal to each other to get 71=10x+1. Subtract 1 from both sides to get 70=10x. Divide both sides by 10 and x=7. Now substitute x in each side of the triangle and we get 7, (4*7-7), and (5*7+8). Solve all of those to get sides of 7, 21, and 43. The question asks what is the length of the longest side, so the answer would be 43.

5 0
3 years ago
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