B = (1/6).π.x².s
1st Multiply both sides with 6 → 6B = (6).(1/6).π.x².s. Simplify by 6
6B = π.x².s. Now divide both sides by .π.x².
6B/(.π.x²) = .(π.x².s)/(.π.x²) After simplification you get:
6B/(.π.x²) = s → s = 6B/(.π.x²)
Assume that,
The two angles of one triangle are congruent to two angles of a second triangle.
To prove: The third angles of the triangles are congruent.
Since, two angles of one triangle are congruent to two angles of a second triangle.
Therefore,

Adding these two we get,

Cancelling 180 on both sides, we get

Hence, if two angles of one triangle are congruent to two angles of a second triangle, the the third angles of the triangles are congruent.
Answer:
Step-by-step explanation:
x=20
Reorder the terms:
(2 + 5x) = 3(x + 14)
Remove parenthesis around (2 + 5x)
2 + 5x = 3(x + 14)
Reorder the terms:
2 + 5x = 3(14 + x)
2 + 5x = (14 * 3 + x * 3)
2 + 5x = (42 + 3x)
Solving
2 + 5x = 42 + 3x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-3x' to each side of the equation.
2 + 5x + -3x = 42 + 3x + -3x
Combine like terms: 5x + -3x = 2x
2 + 2x = 42 + 3x + -3x
Combine like terms: 3x + -3x = 0
2 + 2x = 42 + 0
2 + 2x = 42
Add '-2' to each side of the equation.
2 + -2 + 2x = 42 + -2
Combine like terms: 2 + -2 = 0
0 + 2x = 42 + -2
2x = 42 + -2
Combine like terms: 42 + -2 = 40
2x = 40
Divide each side by '2'.
x = 20
Simplifying
x = 20
Answer:
4063/1274
Step-by-step explanation:
I suggest using photo math app after update it has improved
Let's see what to do buddy...
_________________________________
The sum of the angles of each n-sided figure is found in the following equation :

The question's figure is 5-sindes figure
so the sum the angles equal :

So we have :


Subtract the sides of the equation minus 479


And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️