Solve for B6=10B+12C
2 answers:
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Answer:
1) Randomization condition: We assume that we are selecting random samples so this condition is satisfied
2) 10% condition: We assume that the random sample selected is less than 10% of the population size
3) Success/ Failure condition:
For this case we need to satisfy this:
So since the condition 1 and 2 are satisfied the correct option for this case would be:
a)np and nq must be respectively at least equal to 10
Step-by-step explanation:
Assuming the following options:
a)np and nq must be respectively at least equal to 10
b) as n increases, the distribution of sample proportions becomes less Normal
c) np and nq must be respectively less than 10
d) np plus nq must be at least 10.
For this case we need 3 basic conditions:
1) Randomization condition: We assume that we are selecting random samples so this condition is satisfied
2) 10% condition: We assume that the random sample selected is less than 10% of the population size
3) Success/ Failure condition:
For this case we need to satisfy this:
So since the condition 1 and 2 are satisfied the correct option for this case would be:
a)np and nq must be respectively at least equal to 10
The image of circle A is missing, so i have attached it;
Answer:
x = 17
Step-by-step explanation:
In Δs EAB and EAD
We are told that;
∠BAE ≅ ∠DAE
AB = AD = AE
Now,
The Two triangles have two corresponding equal sides and the angles between them are equal, thus, we can say that the two triangles are congruent by SAS (Side Angle Side) postulate of congruence
By using the result of congruence, we can say that;
EB ≅ ED
We are given that;
EB = 3x - 24 and ED = x + 10
Thus,
3x - 24 = x + 10
∴ 3 x - 24 = x + 10
Add 24 to both sides to give;
3x = x + 34
Subtract x from both sides to give;
2x = 34
Divide both sides by 2 to give;
x = 17
