Solve for a. a^2=-3a+88

Mathematics

1 answer:

Sergio [31]2 years ago

5 0

Answer:

$a=8,-11$

Step-by-step explanation:

$a^2=-3a+88$

$a^2+3a=88$

$a^2+3a-88=0$

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\frac{-3\pm\sqrt{3^2-4(1)(-88)} }{2(1)}$

$x=\frac{-3\pm\sqrt{9+352} }{2}$

$x=\frac{-3\pm\sqrt{361} }{2}$

$x=\frac{-3\pm19 }{2}$

$x=-11$ and $x=8$

Therefore, the values of $a$ are 8 and -11.

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