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Aloiza [94]
3 years ago
12

Find the perimeter of the figure. Yes 3x (2x + 5)

Mathematics
2 answers:
Dahasolnce [82]3 years ago
8 0

Answer:

6x2+15x

Step-by-step explanation:

strojnjashka [21]3 years ago
8 0
6x^2+15x that is the correct answer
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What number must you add to -6 to get a sum of zero? Explain
Lena [83]
You would have to add a positive 6 to the negative 6 to get zero. Lets say you have -2 in order to get it to zero or just any positive number, you have to add a positive of the same value or higher to be able to get it there. I hope you understand that.
6 0
3 years ago
Two buses leave a station at the same time and travel in opposite directions. One bus travels 15 /kmh faster than the other. If
Nat2105 [25]
Since the buses travel in opposite directions, the speed at which they distance themselves is the sum of their speeds.
One bus travels at speed s.
The other bus travels at speed s + 15.
The sum of the speeds is s + s + 15 = 2s + 15

speed = distance/time

distance = speed * time

366 = (2s + 15) * 2

183 = 2s + 15

168 = 2s

s = 84

The slower bus travels at 84 km/h.

s + 15 = 84 + 15 = 99

The faster bus travels at 99 km/h.

Check:
In 2 hours, the slower bus travels 2 * 84 km = 168 km
In 2 hours, the faster bus travels 2 * 99 km = 198 km
In 2 hours, the buses are 198 km + 168 km = 366 km apart.
Our answer is correct.
6 0
3 years ago
Use the rule 2 + 3 to find the missing number on the table.
vfiekz [6]

Answer:

14

Step-by-step explanation:

11 + 3 = 14

Hope it helps!

Thanks!

7 0
3 years ago
In angle STU, u = 890 cm, t = 810 cm and angle T=38°. Find all possible values of angle U, to the nearest degree.
erastova [34]

Answer:

754435.345345435.43.5435435454.35.34.543534.5.43.5.43.545

Step-by-step explanation:

7 0
3 years ago
What is the solution to the system of equations? x=4y 6 x-3y=4
ahrayia [7]
If you graph the two equations then you will find that they intersect at (-2,-2).

You then have to check your answer.

x=4y+6
(-2)=4(-2)+6
-2=-8+6
-2=-2

x-3y=4
(-2)-3(-2)=4
-2+6=4
4=4

8 0
3 years ago
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