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3 years ago

A circle whose area is 4 has a radius of x find the area of a circle whose radius is 3x

2 answers:

7 0

The first one is 1.12867 because you need to set it up like this.
4=3.14(x)squared
4/3.14=x(squared)
x=1.12867

The second one is done simply by multiplying it out.
A=3.14(3x)squared
A=3.14(9x[squared])
A=28.26x[squared] -The squared is referring to the x.

stich3 [128]3 years ago

3 0

Answer:

Area = 36 units.

Step-by-step explanation:

Given : A circle whose area is 4 has a radius of x .

To find : find the area of a circle whose radius is 3x.

Solution: We have given

Area of circle = 4 units.

Radius = x .

Formula of area = pi (radius)².

Plug the values

pi (x)² = 4 -------(A)

If the radius = 3x .

Then 4

Area = pi (3x)².

Area = pi (9)(x)².

Area = 9 pi (x)²-----(B) .

We can see from equation ( A) 4 = pi (x)²

Area = 9 * 4.

Area = 36 units.

Therefore, Area = 36 units.

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Vladimir79 [104]

Answer:

The time interval when $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

$V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)$

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

$V_Q(t) \geq 60$ between $0 \leq t \leq 4$

The schematic free body graphical representation of the above illustration was attached in the file below and the point when $V_Q(t) \geq 60$ is at 4 is obtained in the parabolic curve.

So, $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

Taking the integral of the time interval in order to determine the distance; we have:

distance = $\int\limits^{3.519}_{1.866} {V_Q(t)} \, dt$

= $\int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt$

= By using the Scientific calculator notation;

distance = 106.109 m

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3 years ago