Answer:
.33 as a decimal or 33%
Step-by-step explanation:
Divide 1/3 and get .33 as your decimal. To convert to a percentage multiply your decimal by 100. (<em>.33 x 100 = 33 </em>)
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The equation of the line of best fit using the slope-intercept formula y=mx+b is y = x - 5
<h3>Equation of the line of best fit</h3>
A line is the shortest distance between two points. The equation in point-slope form is expressed as:
y =. mx + b
m is the slope
b is the y intercept
Using the coordinate points (25, 20) and (60, 55)
Slope = 55-20/60-25
Slope = 35/35
Slope = 1
For the intercept
20 = 1(25) + b
b = 20 - 25
b = -5
Substitute
y = x + (-5)
y = x - 5
Hence the equation of the line of best fit using the slope-intercept formula y=mx+b is y = x - 5
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The two-sided alternative hypothesis is appropriate in this case, the reason being we are asked "does the data indicate that the average body temperature for healthy humans is different from 98.6◦........?".
The test statistic is:

Using an inverse normal table, and halving

for a two-tailed test, we look up

and find the critical value to be Z = 2.5758.
Comparing the test statistic Z = -5.47 with the rejection region Z < -2.5758 and Z > 2.5758. we find the test statistic lies in the rejection region. Therefore the evidence does not indicate that the average body temperature for healthy humans is different from 98.6◦.
the Pythagorean Theoremproof of let ΔABC be a right triangle. and sinA=a/c, and cosA= b/ca opposite side of the angle Ab the adjacent side of the angle Aand c is the hypotenuswe know that sin²A +cos²A= (a/c)²+ (b/c) ², but sin²A +cos²A=1so, a²/c²+ b²/c ²=1 which implies a²+ b²=c² the answer is Transitive Property of Equality proof the right triangles BDC and CDA are siWe start with the original right triangle, now denoted ABC, and need only one additional construct - the altitude AD. The triangles ABC, DBA, and DAC are similar which leads to two ratios:AB/BC = BD/AB and AC/BC = DC/AC.Written another way these becomeAB·AB = BD·BC and AC·AC = DC·BCSumming up we getAB·AB + AC·AC= BD·BC + DC·BC = (BD+DC)·BC = BC·BC.so not in the proof is Transitive Property of Equality