<u><em>Answer:</em></u>
- 84x - 70
<em><u>Step-by-step explanation:</u></em>
We want to combine like terms:
-10 - 90x + 6x - 60
We can see (-10) and (-60) are both regular constants so:
- 10 - 60 = - 70
Then (-90x) and (+ 6x):
6x - 90x = - 84x
- 84x - 70
Answer:
x=0.5355 or x=-6.5355
First step is to: Isolate the constant term by adding 7 to both sides
Step-by-step explanation:
We want to solve this equation: 
On observation, the trinomial is not factorizable so we use the Completing the square method.
Step 1: Isolate the constant term by adding 7 to both sides

Step 2: Divide the equation all through by the coefficient of
which is 2.

Step 3: Divide the coefficient of x by 2, square it and add it to both sides.
Coefficient of x=6
Divided by 2=3
Square of 3=
Therefore, we have:

Step 4: Write the Left Hand side in the form 

Step 5: Take the square root of both sides and solve for x

You are right. In circle equation we have =r² so the correct answer will be C od D. But we have to calculate the center of a circle.

Complete the square:

And we have:

So the answer is C (the same left side of equation).
Since you need a little bit of trigonometry to solve this problem,
I'm pretty sure you've had a little bit of trigonometry in class before
you were assigned to solve this problem.
-- The shaded triangle comes from taking the equilateral triangle and
either folding it in half or cutting it in half.
-- The base that the new triangle is standing on is 1/2 the base of the
equilateral triangle, so it's 7 cm long.
-- The acute angle at the right end of the base is the same as it was in
the equilateral triangle . . . 60 degrees.
-- The tangent of 60 degrees is (opposite side)/(adjacent side) = x / 7 cm
tan(60) = x/7
-- Multiply each side of this little equation by 7 : 7 tan(60) = x
If you don't have the tangent of 60 degrees in your pocket, you can
find it with your calculator. Multiply it by 7, and Shazam, you know 'x' .
Answer:
Belle is my fav.
Step-by-step explanation:
She loves to read books like me and I hate people who always go out there and try to impress me with something.