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ad-work [718]
3 years ago
5

8:54 a.m.

Mathematics
1 answer:
dimaraw [331]3 years ago
5 0
Hello,

The two lights flash at the same time every 18 min
at 8:00 h=480 min =480+0*36
at 8:36 h=516 min =480+1*36
...
54 is not divisible by 36
60+12=72 = 2*36 yes
60+24=84 not
120+24=4*36 yes
180+18=198 not

So 2 times are correct 9:12 and 10:24
Answer G


 

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Simplify: -10 - 90x + 6x - 60
antoniya [11.8K]

<u><em>Answer:</em></u>

- 84x - 70

<em><u>Step-by-step explanation:</u></em>

We want to combine like terms:

-10 - 90x + 6x - 60

We can see (-10) and (-60) are both regular constants so:

- 10 - 60 = - 70

Then (-90x) and (+ 6x):

6x - 90x = - 84x

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4 0
3 years ago
Solve this equation for x: 2x^2 + 12x - 7 = 0
zhannawk [14.2K]

Answer:

x=0.5355 or x=-6.5355

First step is to: Isolate the constant term by adding 7 to both sides

Step-by-step explanation:

We want to solve this equation: 2x^2 + 12x - 7 = 0

On observation, the trinomial is not factorizable so we use the Completing the square method.

Step 1: Isolate the constant term by adding 7 to both sides

2x^2 + 12x - 7+7 = 0+7\\2x^2 + 12x=7

Step 2: Divide the equation all through by the coefficient of x^2 which is 2.

x^2 + 6x=\frac{7}{2}

Step 3: Divide the coefficient of x by 2, square it and add it to both sides.

Coefficient of x=6

Divided by 2=3

Square of 3=3^2

Therefore, we have:

x^2 + 6x+3^2=\frac{7}{2}+3^2

Step 4: Write the Left Hand side in the form (x+k)^2

(x+3)^2=\frac{7}{2}+3^2\\(x+3)^2=12.5\\

Step 5: Take the square root of both sides and solve for x

x+3=\pm\sqrt{12.5}\\x=-3\pm \sqrt{12.5}\\x=-3+ \sqrt{12.5}, $ or $x= -3- \sqrt{12.5}\\$x=0.5355 or x=-6.5355

6 0
3 years ago
Which equation represents the circle described? (in picture)
Sedaia [141]
You are right. In circle equation we have =r² so the correct answer will be C od D.  But we have to calculate the center of a circle.

x^2+y^2-8x-6y+24=0\quad|-24\\\\(x^2-8x)+(y^2-6y)=-24

Complete the square:

x^2-8x+a^2\implies a=\dfrac{8x}{2x}=4\implies x^2-8x+4^2\\\\\\y^2-6y+b^2\implies b=\dfrac{6y}{2y}=3\implies y^2-6y+3^2

And we have:

(x^2-8x)+(y^2-6y)=-24\\\\(x^2-8x+4^2)-4^2+(y^2-6y+3^2)-3^2=-24\\\\&#10;(x-4)^2+(y-3)^2-16-9=-24\\\\(x-4)^2+(y-3)^2-25=-24\quad|+25\\\\\boxed{(x-4)^2+(y-3)^2=1}

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6 0
3 years ago
I'm really lost on this problem
Alenkinab [10]
Since you need a little bit of trigonometry to solve this problem,
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-- The base that the new triangle is standing on is 1/2 the base of the
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-- The acute angle at the right end of the base is the same as it was in
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--  The tangent of 60 degrees is (opposite side)/(adjacent side) = x / 7 cm

              tan(60) = x/7

-- Multiply each side of this little equation by 7 :   7 tan(60) = x
 
If you don't have the tangent of 60 degrees in your pocket, you can
find it with your calculator.  Multiply it by 7, and Shazam, you know 'x' .
5 0
3 years ago
Fun question: Which Disney character is your favorite?
Vlada [557]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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