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bixtya [17]
3 years ago
5

If f(x) = {-3x + 3 for x < 0

Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0

Answer:

The answer is 2.146

Step-by-step explanation:

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The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 5 to 4 . If there were
Kamila [148]
If there were 5 yes votes for every 4 no votes, there were 5 yes votes for every 9 total votes, so 5/9 of the 7911 votes were yes.  5/9*7911=4395.
7 0
2 years ago
Explain why f(x) = x2+4/x2-x-2 is not continuous at x = 2.
xxTIMURxx [149]

Answer: Option a.

Step-by-step explanation:

 Make the denominator equal to zero and solve for x:

Factor the quadratic equation. Find two number whose sum is -1 and whose product is -2. Then:

x^{2}-x-2=0\\(x-2)(x+1)=0\\x=2\\x=-1

Then, as you can see the value x=2 makes the denominator equal to zero and the division by zero does not exist. Therefore you can conclude that the function shown in the problem is not defined at x=2

The answer is the option a.

6 0
3 years ago
Read 2 more answers
Jane wants to pick out an outfit for the school dance . She can choose from 3 pairs of pants 5 shirts and 2 pairs of shoes . How
Alina [70]

Answer:

30

Step-by-step explanation:

we multiply each number. There are 3 pairs of pants 5 shirts and 2 pairs of shoes, so we multiply 3x5x2 to get 30

She should pick out this outfit...

3 0
2 years ago
The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co
Alona [7]

Answer:

95% Confidence interval for the variance:

3.6511\leq \sigma^2\leq 34.5972

95% Confidence interval for the standard deviation:

1.9108\leq \sigma \leq 5.8819

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

s^2=2.89^2=8.3521

The confidence interval for the variance is:

\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128

Then, the confidence interval can be calculated as:

\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819

6 0
3 years ago
(a) Suppose that a person has an average heart rate of 72.0 beats/min. How many beats does he or she have in 2.0 y? (b) In 2.00
Gemiola [76]

Answer:

A= 75686400

B= 7568640000

C= 75686400000

Step-by-step explanation:

1 day= 1440 min

1 year= 365 days

365 days*1440 min= 525600 min , 1 year= 525600 min

525600 min*2 years= 1051200 min

(in 2 years) 72 beats*1051200 min= 75686400

(in 200 years) 75686400*100= 7568640000

(in 2000 years) 7568640000*10 =75686400000

3 0
2 years ago
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