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3 years ago

Your friend saves $12 per week. How many weeks will it take your

Mathematics

1 answer:

Volgvan3 years ago

4 0

Step-by-step explanation:

We need to know the cost of the bodyboard in question...

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How do you graph? <br> y=−4/3x+8y

trasher [3.6K]

How do we graph anything? Make a table of values for x and y and then plot each point. After plotting each point on the xy-plane, connect each point with a straight line or curve (depending on the function).

In this case, we must first isolate y.

y = (-4/3)x + 8y

y - 8y = (-4/3)x

-7y = (-4/3)x

y = (-4/3)x ÷ (-7)

y = (4/21)x

Now follow the steps above.

8 0

3 years ago

Which is a multiple of 15?<br>a.1<br>b.5<br>c.h<br>d.15

lakkis [162]

15 is you answer sir. the multiples are 15,30,45,60,75<span>,90,105,120,135,150,165,180,195,210,225,240,255,270,285,300,315</span>

4 0

3 years ago

Read 2 more answers

What is the rational number equivalent to 3 point 12 repeating

DerKrebs [107]

The answer is 103/33.

8 0

3 years ago

What is the value of L-1.1)?<br>

stepladder [879]

Answer:

-2

Step-by-step explanation:

The floor function returns the largest integer not greater than the function's argument. The largest integer less than or equal to -1.1 is -2.

7 0

4 years ago

1.How many combinations are possible from the letters HOLIDAY if the letters are taken?

Lesechka [4]

Using the combination formula, it is found that:

1. A. 7 combinations are possible.

B. 21 combinations are possible.

C. 1 combination is possible.

2. There are 245 ways to group them.

<h3>What is the combination formula?</h3>

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by:

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Exercise 1, item a:

One letter from a set of 7, hence:

$C_{7,1} = \frac{7!}{1!6!} = 7$

7 combinations are possible.

Item b:

Two letters from a set of 7, hence:

$C_{7,2} = \frac{7!}{2!5!} = 21$

21 combinations are possible.

Item c:

7 letters from a set of 7, hence:

$C_{7,7} = \frac{7!}{0!7!} = 1$

1 combination is possible.

Question 2:

Three singers are taken from a set of 7, and four dances from a set of 10, hence:

$T = C_{7,3}C_{10,4} = \frac{7!}{3!4!} \times \frac{10!}{4!6!} = 245$

There are 245 ways to group them.

More can be learned about the combination formula at brainly.com/question/25821700

6 0

2 years ago