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FromTheMoon [43]
2 years ago
10

1.How many combinations are possible from the letters HOLIDAY if the letters are taken?

Mathematics
1 answer:
Lesechka [4]2 years ago
6 0

Using the combination formula, it is found that:

1. A. 7 combinations are possible.

B. 21 combinations are possible.

C. 1 combination is possible.

2. There are 245 ways to group them.

<h3>What is the combination formula?</h3>

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by:

C_{n,x} = \frac{n!}{x!(n-x)!}

Exercise 1, item a:

One letter from a set of 7, hence:

C_{7,1} = \frac{7!}{1!6!} = 7

7 combinations are possible.

Item b:

Two letters from a set of 7, hence:

C_{7,2} = \frac{7!}{2!5!} = 21

21 combinations are possible.

Item c:

7 letters from a set of 7, hence:

C_{7,7} = \frac{7!}{0!7!} = 1

1 combination is possible.

Question 2:

Three singers are taken from a set of 7, and four dances from a set of 10, hence:

T = C_{7,3}C_{10,4} = \frac{7!}{3!4!} \times \frac{10!}{4!6!} = 245

There are 245 ways to group them.

More can be learned about the combination formula at brainly.com/question/25821700

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If sammmy has 5 alligators biting and each have 100 hunred teeth how many bite marks would he have?
posledela
Hello!

We are given that each of the 5 alligators has 100 teeth. We can use the following equation to find the total number of teeth and, by extension, the total number of bite marks:

(100 teeth) × (5 alligators) = 500 teeth

We have now proven that the 5 alligators have a combined total of 500 teeth. Consequently, Sammy will have 500 bite marks.

I hope this helps!

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3 years ago
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GenaCL600 [577]

Answer:

4

Step-by-step explanation:

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NO LINKS!! Please help me with this problem​
iogann1982 [59]

{\qquad\qquad\huge\underline{{\sf Answer}}}

The given figure shows a vertical hyperbola with its centre at origin, and as we observe the figure, we can conclude that :

Length of transverse axis is :

\qquad \sf  \dashrightarrow \: 2b = 12

\qquad \sf  \dashrightarrow \: b = 6

length of conjugate axis is :

\qquad \sf  \dashrightarrow \: 2a = 8

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\qquad \sf  \dashrightarrow \:    \cfrac{ {y}^{2} }{ {b}^{2} } - \cfrac{  {x}^{2} }{ {a}^{2} }  = 1

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If all city buses carry the same number of passengers, what is the least number of buses needed to carry 710 passengers? 5 10 11
noname [10]

The least number of buses needed to carry 710 passengers is 5.

Option A)5 is the correct answer.

<h3>What is the least number of buses needed to carry 710 passengers? </h3>

Given that;

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  • Least number of buses need B = ?

To get the least number of buses, we say;

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The least number of buses needed to carry 710 passengers is 5.

Option A)5 is the correct answer.

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