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dlinn [17]
3 years ago
13

How many times will interest be added to the principal in 1 year if the interest is compounded annually?

Mathematics
2 answers:
jeka57 [31]3 years ago
7 0
If it's compounded annually, it basically means the interest rate will apply once a year.

So the answer will be 1. 
Naddika [18.5K]3 years ago
4 0

Answer:

Once.

Step-by-step explanation:

We are asked to find the number of times interest will be added to the principal in 1 year if the interest is compounded annually.

We know that compounding annually means that interest is added to the principal once in a  year.

Therefore, the interest is added once to the principal in 1 year if the interest is compounded annually.

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I don't know the answer to this and I've been stuck on it for a while now. Please can someone answer this
Natasha_Volkova [10]
Multiply each term by 8 ( to get rid of the fractions) 
we get:-
-72 = -16 - k

k = -16 + 72 = 56 answer
8 0
3 years ago
Please help mee What is the smallest positive integer whose proper divisors add up to more than the integer itself?
Law Incorporation [45]

Answer:

12

Step-by-step explanation:

The proper divisors of 12 are

1 2 3 4 6

Add those together you get 16

8 0
3 years ago
Write 10 12/5 as an equivalent improper fraction
romanna [79]
10 \frac{12}{5} = \frac{(10 X 5 ) + 12}{5} 
= \frac{62}{5}
8 0
4 years ago
Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm
GuDViN [60]
Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones). 

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

P(x \ \textless \  3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \  3) \approx 0.00951836732 }


Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.


5 0
4 years ago
What does four more than one-third x
Angelina_Jolie [31]

Answer:

it means 4 times 1/3x

4x/3

​

3 0
3 years ago
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