3 years ago

−4v−4v>8 What’s the answer

Mathematics

1 answer:

klio [65]3 years ago

4 0

Answer:

If you have to solve for v, it's v<-1

interval notation: (- ∞, -1)

Step-by-step explanation:

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Part - A

Oduvanchick [21]

Answer:

rule add 15 subtract 10

Step-by-step explanation:

rule add 15 subtract 10

5 0

2 years ago

Figure ABCD is a rhombus where the m∠ABC = 84 and m∠ABE = 3x − 6. Solve for x. Rhombus ABCD with diagonals AC and BD and point E

bazaltina [42]

Answer:

Step-by-step explanation:

See the attched figure

We should know that, one of the properties of the rhombus is the diagonals bisect the angles of the rhombus.

Given:

m∠ABC = 84 and m∠ABE = 3x − 6

So, m∠ABE = 0.5 * m∠ABC = 0.5 * 84 = 42

∴ 3x - 6 = 42

Solve for x

3x = 42 + 6 = 48

x = 48/3 = 16

4 0

3 years ago

Read 2 more answers

For what value of x does 3^4x=27^x-3? a. –9 b. –3 c. 3 d. 9

Irina18 [472]

$\bf 3^{4x}=27^{x-3}\implies 3^{4x}=(3^3)^{x-3}\stackrel{~\hfill \textit{same base, the exponents must also be the same}}{\implies 3^{4x}=3^{3(x-3)}\implies 3^{4x}=3^{3x-9}\qquad } \\\\\\ 4x=3x-9\implies x=-9$

5 0

3 years ago

Consider the compound inequality x < 4 and x>a. If a=4 and the compounding word were "or" instead of "and",what would the

FinnZ [79.3K]

Answer:

We have:

x < 4 AND x > a.

if a = 4 and we use an "or" instead of the "and" we have:

x < 4 or x > 4.

This is:

"x is larger than 4 or smaller than 4."

Then the solution of this is all the real numbers except the value x = 4.

The set of solutions can be written as:

{xI x ∈ R \ [4]}

Where this reads:

"x belongs to the set of the reals minus the number 4".

Or we also could write it as:

x ∈ (-∞, 4) ∪ (4, ∞)

Where we have two open ends in the "4" side, so the value x = 4 does not belong to that set.

4 0

3 years ago

A can is 4 inches wide and 8 inches tall. To the nearest whole number, what is the area of a label that wraps around the can if

Yakvenalex [24]

Answer:

The area of a label is $62.8\ in^{2}$

Step-by-step explanation:

we know that

The lateral area of a cylinder (label of the can) is equal to

$LA=2\pi rh$

we have that

A can is 4 inches wide

The diameter of the can is 4 inches

$r=4/2=2\ in$ ----> the radius is half the diameter

$h=8-3=5\ in$ ----> height of the label

substitute in the formula

$LA=2(3.14)(2)(5)=62.8\ in^{2}$

5 0

3 years ago