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kogti [31]
2 years ago
7

Please help step by step!!!

Mathematics
2 answers:
LenKa [72]2 years ago
8 0

\huge \boxed{\mathfrak{Question} \downarrow}

  • What's the solution of 9 • x = - 63 ?

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\sf \: 9 \cdot x = - 63

Divide both sides by 9.

\sf \: x=\frac{-63}{9}  \\

Divide -63 by 9 to get -7.

\boxed{ \boxed{ \bf \: x=-7 }}

Lesechka [4]2 years ago
5 0

Answer:

-7

Step-by-step explanation:

We first are going to flip the equation around.

So instead of 9 times x = -36 we'll do 36/9. 36/9 = -7.

Also you will kind of know it will be a negative number from the beginning since it's -36.

I don't know if that last part makes any sense, but I hope this helps you!

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Answer:  \bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}

<u>Step-by-step explanation:</u>

(1)           (12, 18, 27, ...)

The common ratio is:

r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\  r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}

(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad  r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\  r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}

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96 divided by 19 is 5.05263157895<span>, so it would be in between 5 and 6!</span>
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