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oksano4ka [1.4K]
4 years ago
15

Amanda uses a rectangular canvas for a panting. The length is 6x-3 centimeters The width is 2x+6 centimeters,and is 4/5of the le

ngth .What are the dimensions of the canva
Mathematics
1 answer:
julia-pushkina [17]4 years ago
7 0

Answer:

15 cm by 12 cm.

Step-by-step explanation:

Given:

Amanda uses a rectangular canvas for a panting.

The length is 6x-3 centimeters.

The width is  2x+6 centimeters, and is 4/5 of the length .

Question asked:

.What are the dimensions of the canvas ?

Solution:

<u>As given that the width is </u>\frac{4}{5} of the length.

2x+6=\frac{4}{5} (6x-3)\\ \\ 2x+6=\frac{4}{5}\times6x-\frac{4}{5}\times3\\ \\ 2x+6=\frac{24x}{5} -\frac{12}{5} \\ \\

Adding both sides by \frac{12}{5}

2x+6+\frac{12}{5} =\frac{24x}{5} -\frac{12}{5}+\frac{12}{5}\\ \\ 2x+\frac{42}{5} =\frac{24x}{5}

Subtracting both sides by 2x

2x-2x+\frac{42}{5} =\frac{24x}{5} -2x\\ \\ \frac{42}{5} =\frac{24x-10x}{5} \\ \\ \frac{42}{5} =\frac{14x}{5} \\ \\

By cross multiplication:-

5\times14x=5\times42\\ \\ 70x=210\\ \\

By diving both sides by 70

x=3

<u>Now, substituting the value:-</u>

The length = 6x-3 cm

                  = 6\times3-3=18-3=15\ cm

The width = 2x+6 cm

                 = 2\times3+6=6+6=12\ cm

Thus, length and width of canvas are 15 cm and 12 cm.

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Find the value of y if B is between A and C, AB is 2y, BC is 6y, and AC is 48.
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7. C. 6

8. H. √34

9. A. (1, 3.5)

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Step-by-step explanation:

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AB + BC = AC (segment addition theorem)

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Let,

P(2, 8) = (x_1, y_1)

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9. Midpoint (M) of segment LB, for L(8, 5) and B(-6, 2) is given as:

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Calculate, to four decimal places, the first ten terms of the sequence. an = 1 +(−4/9)^n
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The first ten terms of the sequence a_n=1 + (-\frac{4}{9} )^n is<em> 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003</em>

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given that:

a_n=1 + (-\frac{4}{9} )^n\\\\When\ n=1:a_1=1 + (-\frac{4}{9} )^1=0.5556\\\\When\ n=2:a_2=1 + (-\frac{4}{9} )^2=1.1975\\\\When\ n=3:a_3=1 + (-\frac{4}{9} )^3=0.9122\\\\When\ n=4:a_4=1 + (-\frac{4}{9} )^4=1.039\\\\When\ n=5:a_5=1 + (-\frac{4}{9} )^5=0.9827\\\\When\ n=6:a_6=1 + (-\frac{4}{9} )^6=1.0077\\\\When\ n=7:a_7=1 + (-\frac{4}{9} )^7=0.9966\\\\When\ n=8:a_8=1 + (-\frac{4}{9} )^8=1.0015\\\\When\ n=9:a_9=1 + (-\frac{4}{9} )^9=0.9993\\\\

When\ n=10:a_{10}=1 + (-\frac{4}{9} )^{10}=1.0003\\

The first ten terms of the sequence a_n=1 + (-\frac{4}{9} )^n is<em> 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003</em>

Find out more on equation at: brainly.com/question/2972832

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