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lbvjy [14]
3 years ago
11

Which algebraic expression is a polynomial? 3m2n – StartFraction 2 m Over n EndFraction + StartFraction 1 Over n EndFraction Sta

rtFraction 2 m n Over 5 EndFraction – StartFraction StartRoot m EndRoot Over 4 EndFraction + 4m5 StartFraction 4 m cubed Over n squared EndFraction – 3mn5 + StartRoot 8 EndRoot 7mn + StartFraction 3 m Over 2 EndFraction + StartFraction 5 n Over 4 EndFraction
Mathematics
2 answers:
Zanzabum3 years ago
8 0

Answer:

d

Step-by-step explanation:

SOVA2 [1]3 years ago
4 0

Answer:

The Answer is D

Step-by-step explanation:

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Prime integers between 1and11​
Roman55 [17]

Answer:

1,3,5,7,11

Step-by-step explanation:

a prime numb er or integer is a number that can not be multiplied to get to other than x1 so for example the only thing you can do for 3 is 3x1 not anything else especially because you said integer

5 0
3 years ago
NEED URGENT HELP!
sp2606 [1]
(3,9)(5,15)
slope = (15 - 9) / (5 - 3) = 6/2 = 3

y = mx + b
slope(m) = 3
(3,9)...x = 3 and y = 9
sub and find b, the y int
9 = 3(3) + b
9 = 9 + b
9 - 9 = b
0 = b

so ur equation is : y = 3x + 0....can be written as y = 3x.

after 12 months...
y = 3x...x = 12
y = 3(12)
y = 36 inches
6 0
3 years ago
I don’t know the answer I’m not that smart help<br><br>Thank you
Stolb23 [73]

Answer:

H

Step-by-step explanation:

The tiny squares equal to 12 already so it is already greater therefore x=0

6 0
3 years ago
What is 16 ÷ 2 x 5 x 3 ÷ 6
aliya0001 [1]

Answer:

20

Step-by-step explanation:

use PEMDAS.

do 5 x 3, the multiply that by 16/2.

you would get 120.

then divide by 6

4 0
3 years ago
Read 2 more answers
Show that the sum of the first 2n natural numbers is n(2n+1)
Leokris [45]

Answer:

This sum is the sum of an arithmetic sequence.  There is a formula for the sum of an arithmetic sequence which can be looked up or derived by a variety of means.

A nice approach for this sequence is the following.  Notice  that the sum of first and last number in the sequence is the same as the sum of the second and second last, and also the same as the sum of the third and third last, and so on.

There are n of these pairs.  So the desired sum is n x (first number + last number).   But the first number is 1 and the last on is 2n.   Thus the desired sum is n(1 + 2n).

Hope this helps!!

Mark Brainleast!!!!!!!!!!!

7 0
2 years ago
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