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faltersainse [42]
3 years ago
12

Can someone help me and explain it

Mathematics
1 answer:
g100num [7]3 years ago
5 0
The answer is D. y=500+0.25x
let's say y represents his total payment each week and x represents his total sales
x=$500
since he always gets 25% bonus of his total sales,
25%.500=0.25x
so, his total payment equals to
y = 500+0.25x
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5(x-2)-3= 5x-13<br>help me plz​
Anna007 [38]
X has infinity solutions.
7 0
2 years ago
Using the quadratic formula to solve 7x2 – x = 7, what are the values of x?
Kruka [31]
How the quadratic formula works:

For any quadratic equation ax² + bx + c = 0, the solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

In the case of our equation 7x² - x = 7, first we need to subtract 7 from each side so that we have 0 on the right.
7x² - x - 7 = 0

Identify the values of a, b, and c.
a = 7, b = -1, and c = -7.

Plug these into our quadratic formula and solve.

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(7)(-7)}}{2(7)}=\boxed{\frac{1\pm\sqrt{197}}{14}

There are two values for x: (1+√197)/14 and (1-√197)/14.
The approximate values for these are 1.073976 and -0.931119.
5 0
3 years ago
Read 2 more answers
Please answer asap. there are two pics :)
Thepotemich [5.8K]

Answer:

\boxed{\sf A. \ 0.34}

Step-by-step explanation:

The first triangle is a right triangle and it has one acute angle of 70 degrees.

We can approximate \sf \frac{WY}{WX} from right triangle 1.

The side adjacent to 70 degrees is WY. The side or hypotenuse is WX.

The side adjacent to 70 degrees in right triangle 1 is 3.4. The side or hypotenuse is 10.

\sf \frac{3.4}{10} =0.34

8 0
3 years ago
8) Jennifer has a collection of 1,600 coins. Of the coins, 40% are dated
Kitty [74]
<h3>Answer:  400  (choice A)</h3>

==============================================

Explanation:

40% + 35% = 75% of the coins were either made before 1940, or made from 1940 to 1980. In other words, 75% of the coins were minted before 1980. This leaves 100% - 75% = 25% of the coins to being minted after 1980.

25% of 1600 = 0.25*1600 = 400 coins were made after 1980

4 0
3 years ago
At age 12 Patrick weighed 43 kg; at age 14 he weighed 50 kg. Patrick’s age and weight are related. A) find a linear equation rel
sergiy2304 [10]

Answer:

A) The equation relating Patrick’s weight to his age is y = 7/2 x + 1

B) The Patrick's age is 10.57 years when he weighed 38 kg

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) and (x2 , y2) is

  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The form of the linear equation is y = mx + c, where m is the slope of

 the line and c is the y-intercept

- The y-intercept means the line intersect the y-axis at point (0 , c)

* Lets solve the problem

- At age 12 Patrick weighed 43 kg

- At age 14 he weighed 50 kg

- Represent the age by x and the weight by y

∴ There are two points on the line which represents the relation

   between the age and the weight of Patrick

∵ (12 , 43) and (14 , 50) belong to the equation relating Patrick’s

  weight to his age

A)

- Lets find the equation

∵ (x1 , y1) is (12 , 43) and (x2 , y2) is (14 , 50)

∴ x1 = 12 , x2 = 14 and y1 = 43 and y2 = 50

∴ m=\frac{50-43}{14-12}=\frac{7}{2}

∵ y = mx + c

∴ y = 7/2 x + c

- To find c by substitute x and y in the equation by the coordinates

 of one of the 2 points

∵ 43 = 7/2 (12) + c

∴ 43 = 42 + c

- Subtract 42 from both sides

∴ c = 1

∴ The equation is y = 7/2 x + 1

* The equation relating Patrick’s weight to his age is y = 7/2 x + 1

B)

∵ The weight of Patrick is 38 kg

- That means y = 38

∵ y = 7/2 x + 1

∴ 38 = 7/2 x + 1

- Subtract 1 from both sides

∴ 37 = 7/2 x

- Divide both sides by 7/2

∴ x = 37 ÷ 7/2 = 10.57

∴ The Patrick's age is 10.57 years when he weighed 38 kg

5 0
3 years ago
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