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faltersainse [42]
3 years ago
12

Can someone help me and explain it

Mathematics
1 answer:
g100num [7]3 years ago
5 0
The answer is D. y=500+0.25x
let's say y represents his total payment each week and x represents his total sales
x=$500
since he always gets 25% bonus of his total sales,
25%.500=0.25x
so, his total payment equals to
y = 500+0.25x
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A space is totally disconnected if its connected spaces are one-point-sets.Show that a finite Hausdorff space is totally disconn
marysya [2.9K]

Step-by-step explanation:

If X is a finite Hausdorff space then every two points of X can be separated by open neighborhoods. Say the points of X are x_1, x_2, ..., x_n. So there are disjoint open neighborhoods U_{12} and U_2, of x_1 and x_2 respectively (that's the definition of Hausdorff space). There are also open disjoint neighborhoods U_{13} and U_3 of x_1 and x_3 respectively, and disjoint open neighborhoods U_{14} and U_4 of x_1 and x_4, and so on, all the way to disjoint open neighborhoods U_{1n}, and U_n of x_1 and x_n respectively. So U=U_2 \cup U_3 \cup ... \cup U_n has every element of X in it, except for x_1. Since U is union of open sets, it is open, and so U^c, which is the singleton \{ x_1\}, is closed. Therefore every singleton is closed.

Now, remember finite union of closed sets is closed, so \{ x_2\} \cup \{ x_3\} \cup ... \cup \{ x_n\} is closed, and so its complemented, which is \{ x_1\} is open. Therefore every singleton is also open.

That means any two points of X belong to different connected components (since we can express X as the union of the open sets \{ x_1\} \cup \{ x_2,...,x_n\}, so that x_1 is in a different connected component than x_2,...,x_n, and same could be done with any x_i), and so each point is in its own connected component. And so the space is totally disconnected.

4 0
4 years ago
Enter the fraction as a decimal
inessss [21]
0.1/0.4 converted to a decimal is 0.25 :) hope this helps
3 0
3 years ago
What is the quotient when (x+3) is divided into the polynomial 2x2+3x-9
maks197457 [2]
Problem: 2x^2+3x-9
For a polynomial of the form, ax^2+bx+c rewrite the middle term as the sum of two terms whose product a·c=2·-9=-18 and whose sum is b=3.
Factor 3 out of 3x
2x^2+3(x)-9
Rewrite 3 as -3 plus 6.
2x^2+(-3+6)x-9
Apply the distributive property
2x^2(-3x+6x)-9
Remove the parentheses
2x^2-3x+6x-9
Factor out the greatest common factor from each group
Group the first two terms and the last two terms
(2x^2-3x) (6x-9)
Factor out the greatest common factor in each group.
x(2x-3)+3(2x-3)
Factor the polynomial by factoring out the greatest common factor, 2x-3
(x+3) (2x-3). So, the quotient is 2x-3



4 0
3 years ago
Read 2 more answers
The pair of points lies on the same line with the given slope. Find x.<br> (4,6). (x, 12); slope = 2
uysha [10]

Answer:

x=7

Step-by-step explanation:

I got this because it is rise over run

\frac{rise}{run} =\frac{6}{?} =2

The missing number would be 3, and if you add that three to 4 you get 7. which means that the answer is...

(7,12)

<h2>Hope this helps you!!!</h2>

6 0
3 years ago
The point (12, 9) is included in a direct variation. What is the constant of variation?
puteri [66]
For direct variation:
y = kx
9 = 12k
k = 9/12 = 3/4
6 0
4 years ago
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