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arlik [135]
3 years ago
9

16a + 7c^2 + 5 - 7a+c

Mathematics
1 answer:
umka21 [38]3 years ago
3 0

Answer:

9a + 7c² + 5 + c

Step-by-step explanation:

16a +  {7}^{2}  + 5 - 7a + c

16a - 7a = (16 - 7)a = 9a

\boxed{\green{= 9a +  {7c}^{2}  + 5 + c}}

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Could someone please explain to me how to solve this problem? Thanks! :)
BartSMP [9]

Answer:

First of all since they are dividing subtract the powers of the base from each other .

Make sure the bases are the same.

((6^7-6)(3^3-4))³

((6)(3^-1))³

(6³)(3^-3)

216 × 1/27

= 8

That's option d.

Hope this helps.

6 0
4 years ago
A savings account is started with an initial deposit of $500. The account earns 1.5% interest compounded annually.
Ghella [55]
A) A=500(1+0.015)^t
b)800=500(1.015)^t
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3 0
3 years ago
You go to the store with $20. You find that packages of gum are on sale for $0.75 per pack. Set up an inequality to
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6 0
3 years ago
1.8n +4= 1.5n - 6.2<br> what is n
marin [14]
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8 0
3 years ago
In a naval engagement, one-third of the fleet was captured, one-sixth was sunk, and two ships were destroyed by fire. One-sevent
Otrada [13]

Answer:

60 ships.

Step-by-step explanation:

Let the total number of ships in the naval fleet be represented by x

One-third of the fleet was captured = 1/3x

One-sixth was sunk = 1/6x

Two ships were destroyed by fire = 2

Let surviving ships be represented by y

One-seventh of the surviving ships were lost in a storm after the battle = 1/7y

Finally, the twenty-four remaining ships sailed home

The 24 remaining ships that sailed home =

y - 1/7y = 6/7y of the surviving fleet sailed home.

Hence

24 = 6/7y

24 = 6y/7

24 × 7/ 6

y = 168/6

y = 28

Therefore, total number of ships that survived is 28.

Surviving ships lost in the storm = 1/7y = 1/7 × 28 = 4

Total number of ships in the fleet(x) =

x = 1/3x + 1/6x + 2 + 28

Collect like terms

x - (1/3x + 1/6x) = 30

x - (1/2x) = 30

1/2x = 30

x = 30 ÷ 1/2

x = 30 × 2

x = 60

Therefore, ships that were in the fleet before the engagement were 60 ships.

3 0
3 years ago
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