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2 years ago

Michael had 4/5 of a spool of yarn. He used 3/5 of it for his project. What fraction of the spool was used for his project?

1 answer:

6 0

You said "He used 3/5 of it for his project " so your question"What fraction of the spool was used for his project?" you already solved dumbas and I copied and pasted your dumb question

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A truck travels 2,365 miles at an average speed of 55 miles per hour.At that speed, how long will it take the truck to complete

disa [49]

Answer:

Step-by-step explanation:

Givens

d = 2365 miles

r = 55 miles / hour

t = ?

Formula

d = r * t

Solution

d = r * t

2365 = 55 * t Divide by 55

2365/55 = t

t = 43 hours.

5 0

2 years ago

What mixed<br> number represents thirty-eighths?

Anvisha [2.4K]

Answer:

............... 3 6/8

4 0

3 years ago

Read 2 more answers

FInd the original price of the tent. A camping store increases the price of a tent by 25%. A customer then uses a $10 coupon for

rosijanka [135]

Answer:

The original price of the tent was $130,00.

Step-by-step explanation:

The original price of the tent will be called "x". The store increased the value by 25%, so the new value is the original one plus 0.25 of the original one, so the new value is 1.25*x. The costummer paid the increased value less the $10 from the coupon, so we have:

paid = 1.25*x - 10

Since he paid $152.5 for the tent we can compute the original value as shown bellow:

152.5 = 1.25*x - 10

1.25*x = 152.5 + 10

1.25*x = 162.5

x = 162.5/1.25 = 130

The original price of the tent was $130,00.

3 0

3 years ago

Read 2 more answers

The vertices of quadrilateral MNPQ are M(-3,-2), N(-1,4), P(2,4), Q(4,-2). Translate quadrilateral MNPQ using the rule (x,y)-&gt

notsponge [240]

Answer:

Here's what I get.

Step-by-step explanation:

The rule is (x, y) ⟶ (x + 3, y + 4).

That means you must move each point three units to the right and four units up. Thus,

M(-3, -2) ⟶ M'(0, 2)

N(-1, 4) ⟶ N'(2, 8)

P(2, 4) ⟶ P'(5, 8)

Q(4, -2) ⟶ Q'(7, 2)

Your quadrilateral is a trapezoid. Both MNPQ and its image M'N'P'Q' are shown in the Figure below.

8 0

3 years ago

Identify the lines that are perpendicular: A. = −5 and = 2 are perpendicularB. + 5 = 2 and − 5 + = 3 are perpendicularC. = 13 +

scZoUnD [109]

In order to check if the lines are perpendicular, we need to check if their slopes have the following relation (to find the slope we can use the slope-intercept form y = mx + b):

$m_1=-\frac{1}{m_2}$

In this option, y = -5 is an horizontal line and x = 2 is a vertical line, therefore they are perpendicular.

First let's find the slope of each line:

$\begin{gathered} x+\frac{y}{5}=2 \\ 5x+y=10 \\ y=-5x+10\to m=-5 \\ \\ -\frac{x}{5}+y=3 \\ y=\frac{x}{5}+3\to m=\frac{1}{5} \end{gathered}$

These slopes obey the relation stated above, so the lines are perpendicular.

$\begin{gathered} y=\frac{1}{3}x+1\to m=\frac{1}{3} \\ \\ y-1=-3(x-5) \\ y-1=-3x+15 \\ y=-3x+16\to m=-3 \end{gathered}$

These slopes obey the relation stated above, so the lines are perpendicular.

$\begin{gathered} y-5=x+1 \\ y=x+6\to m=1 \\ \\ x+y=3 \\ y=-x+3\to m=-1 \end{gathered}$

These slopes obey the relation stated above, so the lines are perpendicular.

$\begin{gathered} y+2=\frac{1}{3}(x-6) \\ y+2=\frac{1}{3}x-2 \\ y=\frac{1}{3}x-4\to m=\frac{1}{3} \\ \\ y=3x+4\to m=3 \end{gathered}$

These slopes don't obey the relation stated above, so the lines aren't perpendicular.

The correct options are A, B, C and D.

5 0

1 year ago