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Arte-miy333 [17]
3 years ago
11

Find the rationalising factor of the irrational number

Mathematics
1 answer:
Zepler [3.9K]3 years ago
8 0
= 3 ⋅ 2

= 6 is the rational numbe
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A leaky faucet has a drip that produces 1.2 drops per second. How many drops will occur in one day?. Show all steps neatly.Write
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3 years ago
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Which Choice is equivalent to the quotient shown here when x is greater or equal to 0
m_a_m_a [10]

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3 similar shirts and 4 similar jackets cost $360. 1 such shirt and 3 such jackets cost $220. Find the costof each shirt.
Lyrx [107]
3s + 4j = 360
1s + 3j = 220

This one we can solve using substitution, in that
s + 3j = 220 implies s = 220 - 3j (subtract 3j from each side).

Now substitute into the first equation:

3(220 - 3j) + 4j = 360.  Solve for jackets.
660 - 9j + 4j = 360  [Distributive property]
660 - 5j = 360 [Add -9j + 4j]
Subtract 360 from each side, and add 5j to each side.
660 - 360 - 5j + 5j = 360 - 360 + 5j
300 = 5j
Divide each side by 5.
$60 = price of a jacket.

Three of these plus a shirt runs $220.
3(60) = 180
180 + s = 220
180 - 180 + s = 220 - 180 [Subtract 180 from each side]
s =   40

Now we double check.
3(40) + 4 (60) = 120 + 240 = 360.  This satisfies the first equation.
We could check the second one too, but I'm satisfied.
4 0
3 years ago
Solve:<br><br><img src="https://tex.z-dn.net/?f=%5Cunderset%7Bx%5Crightarrow~3%7D%7B%5Clim%7D~%5Cdfrac%7B2x%5E2-18%7D%7Bx%5E2-3x
vodomira [7]

Hello, please consider the following.

\displaystyle \lim_{x\rightarrow3}~\dfrac{2x^2-18}{x^2-3x} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x^2-3^2)}{x(x-3)} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x-3)(x+3)}{x(x-3)} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x+3)}{x} \\ \\ \\=\dfrac{2(3+3)}{3}\\ \\ \\=\dfrac{2*3*2}{3} =\Large \boxed{\sf \bf \ 4 \ }

Thank you

8 0
3 years ago
The quadrilateral shown is a rectangle. What is the measure of CE?
aalyn [17]

Answer:

|CE|=2

Step-by-step explanation:

The quadrilateral is shown in the attachment

Recall that the diagonals of a rectangle are congruent.

This implies that:

|AC|=|BD|

We substitute the expressions to get:

2x-6=5x-21

This is now a linear equation in one variable.

Group similar terms to get:

-6+21=5x-2x

Simplify to get:

15=3x

Divide both sides by 3 to get:

5=x

Recall again that the diagonals of a quadrilateral bisect each other.

|CE|=\frac{1}{2}|AC|

|CE|=\frac{1}{2}|2x-6|

Plug x=5

|CE|=\frac{1}{2}|2*5-6| =10-6=\frac{1}{2}*4=2

3 0
4 years ago
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