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3 years ago

How do you do this please

Mathematics

2 answers:

Stels [109]3 years ago

7 0

Your answer would be 7.9

12.166 /-1.54

-7.9

TEA [102]3 years ago

3 0

-12.166 divided by -1.54 hm I think -11.122 Im sorry i never learned this...

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Seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Find the probability that (a)

UNO [17]

Answer:

a) P=0.226

b) P=0.6

c) P=0.0008

d) P=0.74

Step-by-step explanation:

We know that the seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Therefore, we have 46 balls.

a) We calculate the probability that are 3 red, 2 blue, and 2 green balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_3^{12}\cdot C_2^{16}\cdot C_2^{18}=660\cdot 120\cdot 153=12117600$

Therefore, the probability is

$P=\frac{12117600}{53524680}\\\\P=0.226$

b) We calculate the probability that are at least 2 red balls.

We calculate the probability withdrawn of 1 or none of the red balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations: for 1 red balls

$C_1^{12}\cdot C_7^{34}=12\cdot 1344904=16138848$

Therefore, the probability is

$P_1=\frac{16138848}{53524680}\\\\P_1=0.3$

We calculate the number of favorable combinations: for none red balls

$C_7^{34}=5379616$

Therefore, the probability is

$P_0=\frac{5379616}{53524680}\\\\P_0=0.1$

Therefore, the the probability that are at least 2 red balls is

$P=1-P_1-P_0\\\\P=1-0.3-0.1\\\\P=0.6$

c) We calculate the probability that are all withdrawn balls are the same color.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_7^{12}+C_7^{16}+C_7^{18}=792+11440+31824=44056$

Therefore, the probability is

$P=\frac{44056}{53524680}\\\\P=0.0008$

d) We calculate the probability that are either exactly 3 red balls or exactly 3 blue balls are withdrawn.

Let X, event that exactly 3 red balls selected.

$P(X)=\frac{C_3^{12}\cdot C_4^{34}}{53524680}=0.57\\$

Let Y, event that exactly 3 blue balls selected.

$P(Y)=\frac{C_3^{16}\cdot C_4^{30}}{53524680}=0.29\\$

We have

$P(X\cap Y)=\frac{18\cdot C_3^{12} C_3^{16}}{53524680}=0.12$

Therefore, we get

$P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\\\P(X\cup Y)=0.57+0.29-0.12\\\\P(X\cup Y)=0.74$

8 0

3 years ago

What does x= please explain!

Genrish500 [490]

Answer:

x=37°

Step-by-step explanation:

2x°=74° (vertically opposite angles)

2x°/2=74°/2

x=37°

4 0

3 years ago

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Given the graph below, which of the following points would be included in the graph of the inverse of the function?

Svetlanka [38]

Answer : (1,-1)

a line through the points (-1, 1), (0, 2), (1, 3)

To find the point in the graph of inverse function we interchange x and y values

For point (-1 , 1) , the point on inverse function is (1, -1)

For point (0 , 2) , the point on inverse function is (2, 0)

For point (1 , 3) , the point on inverse function is (3, 1)

so (1,-1) will be included in the graph of the inverse of the function

7 0

3 years ago

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Find the area of the iscoseles triangle first answer=brainliest

blsea [12.9K]

Answer:

$60cm^{2}$

Step-by-step explanation:

so first we need to find the height so by splitting the isosceles triangle into two right-angled triangles and then applying Pythagoras' Theorem to one of them.

$h^{2} =13^{2} -5^{2}$

$h^{2} =169-25$

$h^{2} =144$

$h=\sqrt{144}$

$h=12$

We now know the height of the triangle and can use this to go back and find the area of the isosceles triangle.

area of triangle = $\frac{1}{2}$ x base x height

area of triangle = $\frac{1}{2}$ x 10 x 12

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Is 73 a prime number

lora16 [44]

Hi there,

73 indeed a prime number

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3 years ago