How do you do this please
2 answers:
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Answer:
<u>Triangle ABC and triangle MNO</u> are congruent. A <u>Rotation</u> is a single rigid transformation that maps the two congruent triangles.
Step-by-step explanation:
ΔABC has vertices at A(12, 8), B(4,8), and C(4, 14).
- length of AB = √[(12-4)² + (8-8)²] = 8
- length of AC = √[(12-4)² + (8-14)²] = 10
- length of CB = √[(4-4)² + (8-14)²] = 6
ΔMNO has vertices at M(4, 16), N(4,8), and O(-2,8).
- length of MN = √[(4-4)² + (16-8)²] = 8
- length of MO = √[(4+2)² + (16-8)²] = 10
- length of NO = √[(4+2)² + (8-8)²] = 6
Therefore:
- AB ≅ MN
- AC ≅ MO
- CB ≅ NO
and ΔABC ≅ ΔMNO by SSS postulate.
In the picture attached, both triangles are shown. It can be seen that counterclockwise rotation of ΔABC around vertex B would map ΔABC into the ΔMNO.
The value of the P(A∩B) is equal to 0.04.
We have given that,
P(A)= 0.4 and P(B) = 0.85.
We have to determine the P(A and B)
<h3>What is the formula for Independent Events?</h3>For Independent Events,
P(A) × P(B) = P(A∩B)
so we have, P(A∩B) = 0.4×0.1
P(A∩B) = 0.04
P(A') = 1 - 0.4 = 0.6
This information can be represented on a Venn diagram as shown below
P(A'∪B) means the union of everything that is not A with everything that is B
P(A'∪B) = 0.06 + 0.54 + 0.04
P(A'∪B) = 0.64
To learn more about the events visit:
#SPJ1
