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Sunny_sXe [5.5K]
3 years ago
9

which of the graphs shown below represents the base function f(x)=x^2 and the stretched function g(x)=-7/2x^2

Mathematics
1 answer:
IRINA_888 [86]3 years ago
8 0
F(x) = x^2 is the black parabola in both graphs.
g(x) = - 7/2 x^2 tells you the parabola will be:
  - flipped upside down because the negative on the 7/2
  - skinnier, because of the 7/2.

This will be the second graph.
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Please Help !!! its a math problem What is the range of the quadratic equation whose graph contains the following points?
dolphi86 [110]
<h2>Range of a Quadratic Function</h2>

The range tells us the possible <em>y</em>-values that occur in the function.

When describing the range, we can write an inequality using <em>y</em>.

  • Examples: y > 6, y ≤ 10

When describing the range of a quadratic function, we typically use the ≥ or ≤ symbols when writing the inequality.

To write the range of a quadratic function,

  1. Find the vertex
  2. Determine whether the parabola opens up or down
  3. Set <em>y</em> ≥ or ≤ the y-coordinate of the vertex

<h2>Solving the Question</h2>

We're given:

  • Vertex at (0,4)
  • Other points on the graph: (-2,0), (-1,3), (1,3), (2,0)

Because we're directly given the vertex, we just have to determine now whether the parabola opens up or down.

  • If the other points on the graph always have a lower <em>y-</em>coordinate value, then the graph opens down
  • If the other points on the graph always have a greater <em>y-</em>coordinate value, then the graph opens up

The other points that fall on the graph that we're given all have a lower y-coordinate value than 4, that means this parabola opens down.

Therefore, all other y-values for the function will be less than 4.

Therefore, y ≤ 4.

<h2>Answer</h2>

y ≤ 4

4 0
2 years ago
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Answer:

2)y=6

4)36=a

Step-by-step explanation:

8y=48

/8    /8

y=6

18=a/2

*2    *2

36=a

You wanna get x by itself

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hichkok12 [17]

Answer:

The equation of the line that passes through the point (3,-3) and has a slope of 0 will be:

0=y+3

Step-by-step explanation:

The point-slope form of the equation of a line is:

\:y\:-\:y_1\:=\:m\left(x-x_1\right)

where

  • m is the slope of the line and,
  • \left(x_1,\:y_1\right) is a point on the line.

As the slope is m=0, and the point is (3,-3)

so

Equation of the line will be:

\:y\:-\:y_1\:=\:m\left(x-x_1\right)

y\:-\:\left(-3\right)\:=\:0\left(x-3\right)

Further simplifying

0=y-\left(-3\right)

0=y+3

Therefore, the equation of the line that passes through the point (3,-3) and has a slope of 0 will be:

0=y+3

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