Suppose 3
1 answer:
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The correct question is
<span>Which equation can you use to solve for x? x + 56 = 180 x + 146 = 180 180−x=146 x + 56 = 146 The figure contains a pair intersecting lines. One of the four angles formed by the intersecting lines is labeled 146 degrees. The angle opposite and not adjacent to this angle is broken into two smaller angles by a ray that extends from the point where the two lines intersect. One of these smaller angles is labeled 56 degrees, and the other smaller angle is labeled x degrees.
see the picture attached to better understand the problem
we know that
angle 146</span>° and angle (56°+x°) area equal -----> by vertical angles
so
146=56+x
therefore
the answer is
<span>x + 56 = 146</span>
<span>Which equation can you use to solve for x? x + 56 = 180 x + 146 = 180 180−x=146 x + 56 = 146 The figure contains a pair intersecting lines. One of the four angles formed by the intersecting lines is labeled 146 degrees. The angle opposite and not adjacent to this angle is broken into two smaller angles by a ray that extends from the point where the two lines intersect. One of these smaller angles is labeled 56 degrees, and the other smaller angle is labeled x degrees.
see the picture attached to better understand the problem
we know that
angle 146</span>° and angle (56°+x°) area equal -----> by vertical angles
so
146=56+x
therefore
the answer is
<span>x + 56 = 146</span>
<h2>Answer:</h2>
As the question states,
John's brother has Galactosemia which states that his parents were both the carriers.
Therefore, the chances for the John to have the disease is = 2/3
Now,
Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.
Now, one of those children married with a person.
So,
Probability for the child to have disease will be = 1/2
Now, again the child's child (Martha) probability for having the disease is = 1/2.
Therefore,
<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>
(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)
<em><u>Hence, the probability for the first child to have Galactosemia is </u></em>